Chebyshev’s Theorem establishes that at least 1 - 1/k² of the population lie among k standard deviations from the mean.
This means that for k = 2, 1 - 1/4 = 0.75. In other words, 75% of the total population would be the percentage of healthy adults with body temperatures that are within 2standard deviations of the mean.
The maximum value of that range would be simply μ + 2s, where μ is the mean and s the standard deviation. In the same way, the minimum value would be μ - 2s:
maximum = μ + 2s = 98.16˚F + 2*0.56˚F = 99.28˚F
minimum = μ - 2s = 98.16˚F - 2*0.56˚F = 97.04˚F
In summary, at least 75% of the amount of healthy adults have a body temperature within 2 standard deviations of 98.16˚F, that is to say, a body temperature between 97.04˚F and 99.28˚F.
Answer:
ET = 80/A^2
Step-by-step explanation:
First, isolate the variables that you need, which is E and T, using the two equations you were given.
EA = 8
E = 8/A (divide A on both sides to isolate E)
AT = 10
T = 10/A (divide A on both sides to isolate T)
Now, substitute.
ET --> (8/A) x (10/A) = 80/A^2
Answer:
i think it's -1 / -1
nut i'm not sure so if its wrong then sorry , and don't thank's me...
Answer: 1 1/5
Step-by-step explanation: 3/5 is the radius so you would times the radius by two to get the diameter which is 1 1/5.