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3 years ago

7

Find the area of a circle with a diameter

2 answers:

Maslowich3 years ago

6 0

To get the answer divide the diameter by two, so you can get the radius. So plug it into the formula A=π 8²=π (8²)=64π =200.96 and for multiplying pie I just used 3.14 instead the entire number so I could get it by having the decimal in the hundredths place.

koban [17]3 years ago

6 0

64 pi. Half of 16 is 8 and 8 squared is 64.

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Hello i really need help, please help me. thank you :(

vlabodo [156]

Answer:

12/13

Step-by-step explanation:

The cosine of an angle in a triangle can be calculated as a relation between the adjacent side and the hypothenuse. So, in this case the adjacent side of θ is 24 and the hypothenuse is 26.

Then:

cos(θ) = 24/26 = 12/13

6 0

3 years ago

Read 2 more answers

By how much does the dependent variable change in response to a change of 1 unit of the independent variable?

dalvyx [7]

Answer: C) 5

--------------

x = independent variable, y = dependent variable

Assuming this is a linear function, each increase of x by 2 leads to y going up by 10. So 10/2 = 5 is the unit increase each time x bumps up by 1.

-------------------

An alternative is to use the slope formula to get

m = (y2 - y1)/(x2 - x1)

m = (25 - 15)/(4 - 2)

m = 10/2 <--- this expression shows up again

m = 5 <---- leading to the same answer as before

So we see that the slope formula is a more drawn out method to finding the answer.

6 0

3 years ago

Read 2 more answers

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Can someone please help me with this?

Fantom [35]

Answer:

step 1: 100

step 2: is 100

Step 3: 5,600

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Could you please Factor 12 + 16

-BARSIC- [3]

If you add that together you get 28

7 0

3 years ago