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Novay_Z [31]
3 years ago
9

A new college, The University of Discrete Structures, is opening in Boulder! Ioana and Rachel are its founders and are holding a

meeting to determine how many different courses to offer. The following rules are being insisted on: Each course must meet in a different building on the UDS campus, and no two students enrolled at the college may take the exact same set of courses. This means that for any two students, their list of courses that they are taking must differ by at least one course. It is required that all students enroll in at least one course. You must fully justify the following questions: (a) If there are 500 students enrolled in the new university, what is the smallest number of buildings that will be needed to host classes? (b) In general, with n different buildings, what is the maximum number of students that can enroll in the university so that rules are still met?
Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

Answer:

  (a) 9 buildings

  (b) 2^n -1

Step-by-step explanation:

The number of distinct non-empty subsets of b objects is 2^b -1. Since the subsets are distinct, each could represent a list of the buildings, from the set of b buildings, in which a student is taking courses.

(a) For 8 buildings, 2^8 -1 = 255 students could enroll. for 9 buildings, 2^9-1 = 511 students could enroll.

For 500 students, 9 buildings are required.

__

(b) The maximum number of students for n buildings is ...

  2^n -1

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FromTheMoon [43]

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6 X2 6X-72

Step-by-step explanation:

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3 years ago
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goldenfox [79]

Answer:

10

Step-by-step explanation:

7 0
3 years ago
Kindly answer this question it would be really helpfull
Svetach [21]

Answer:

The values in the table, taking into account the quadratic equation, are:

  • x     -3     -2     -1     0     1     2     3     4
  • y     <u>16</u>      9     <u>4</u>     1     <u>0</u>     1     <u>4</u>     9

Step-by-step explanation:

To obtain the values of the table, you must use the quadratic equation given:

  • <u>y = x^2 - 2x + 1</u>

Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:

  • y = x^2 - 2x + 1
  • y = (-3)^2 - 2*(-3) + 1
  • y = 9 + 6 + 1
  • <u>y = 16</u>

When x is -1

  • y = x^2 - 2x + 1
  • y = (-1)^2 - 2*(-1) + 1
  • y = 1 + 2 + 1
  • <u>y = 4</u>

When x is 1

  • y = x^2 - 2x + 1
  • y = (1)^2 - 2*(1) + 1
  • y = 1 - 2 + 1
  • <u>y = 0</u>

When x is 3:

  • y = x^2 - 2x + 1
  • y = (3)^2 - 2*(3) + 1
  • y = 9 - 6 + 1
  • <u>y = 4</u>

At last, the graph must be as the attached picture I give you, but <u><em>remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider</em></u>.

3 0
3 years ago
find the volume of cubical box . if the cost of painting of outer surface is rs 1440 at the rate rs 15 per mcube
bearhunter [10]
Surface of a cubical box=6(side²)

1)We have to calculate the surface of this cubical box.
Rate=cost of painting / surface  ⇒surface=cost of painting/rate

Data:
Rate=$15/m²
cost of painting=$1440

Surface=$1440/($15/m²)=96 m²

2)We find out the length of the side:

Surface of a cubical box=6(side²)

Data:
Surface of a cubical box=96 m2

Therefore:
96m²=6 (side²)
side²=96 m²/6
side²=16 m²
side=√(16 m²)=4 m

3) We find the volume of a cubical box.
volume=(side³)
volume=(4 m)³
volume=64 m³

Answer: the volume of this cubical box would be 64 m³.

3 0
3 years ago
Apr 17, 1:42:09 AM
SVEN [57.7K]

Answer:

(-1, 5)

Step-by-step explanation:

3 [x + y = 4]

  3x + 3y = 12

-  3x + 7y = 32

-4y = -20

y = 5

x + 5 = 4

x = -1

3 0
2 years ago
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