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Novay_Z [31]
4 years ago
9

A new college, The University of Discrete Structures, is opening in Boulder! Ioana and Rachel are its founders and are holding a

meeting to determine how many different courses to offer. The following rules are being insisted on: Each course must meet in a different building on the UDS campus, and no two students enrolled at the college may take the exact same set of courses. This means that for any two students, their list of courses that they are taking must differ by at least one course. It is required that all students enroll in at least one course. You must fully justify the following questions: (a) If there are 500 students enrolled in the new university, what is the smallest number of buildings that will be needed to host classes? (b) In general, with n different buildings, what is the maximum number of students that can enroll in the university so that rules are still met?
Mathematics
1 answer:
Rama09 [41]4 years ago
3 0

Answer:

  (a) 9 buildings

  (b) 2^n -1

Step-by-step explanation:

The number of distinct non-empty subsets of b objects is 2^b -1. Since the subsets are distinct, each could represent a list of the buildings, from the set of b buildings, in which a student is taking courses.

(a) For 8 buildings, 2^8 -1 = 255 students could enroll. for 9 buildings, 2^9-1 = 511 students could enroll.

For 500 students, 9 buildings are required.

__

(b) The maximum number of students for n buildings is ...

  2^n -1

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The question is in the picture.
dangina [55]
<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0
3 years ago
Multiply the two mixed numbers 4 1/2 x 3 2/3 simplify your answer and write it as a mixed number
konstantin123 [22]

Answer: 16 1/2

Step-by-step explanation:

It's easiest to multiply improper fractions and then to convert them back into mixed numbers, so 4 1/2 would become 9/2 and 3 2/3 would become 11/3. \frac{9}{2} *\frac{11}{3}= 99/6. Now just simplify to 33/2 and then convert back into a mixed number.  16 1/2

8 0
3 years ago
PLEASE URGENTLY ANSWER THESE 2 QUESTIONS, I WILL PROVIDE MORE POINTS AND CROWN YOU BRAINLIEST IF YOU DO!!!
Doss [256]

Answer:

1. I would think it would be a appropriate to use a normal model to figure this out because sometimes when you are using stuff online you can get the same number like 20 times in a row, whereas, if you use a real dice, you most likely won't roll the same number 20 times.

2. { sorry two doesn't make sense }

6 0
3 years ago
an investment of ​$101 comma 000 was made by a business club. the investment was split into three parts and lasted for one year.
GaryK [48]

Answer:

unknown

Step-by-step explanation:

I am sorry but part of your question is missing

3 0
3 years ago
A frog moves in a sequence of unit steps. Each step is N, S, E or W with equal probability. It starts at the origin. Find the pr
Molodets [167]

The answer is 067.

It takes an even number of steps for the object to reach (2,2), so the number of steps the object may have taken is either 4 or 6 .

If the object took 4 steps, then it must have gone two steps $\mathrm{N}$ and two steps E, in some permutation. There are $\frac{4 !}{2 ! 2 !}=6$ ways for these four steps of occuring, and the probability is $\frac{6}{4^{4}}$.

If the object took 6 steps, then it must have gone two steps N and two steps E, and an additional pair of moves that would cancel out, either N / S or W/E. The sequences N, N, N, E, E, S can be permuted in $\frac{6 !}{3 ! 2 ! 1 !}=60$ ways. However, if the first four steps of the sequence are N, N, E, E in some permutation, it would have already reached the point (2,2) in four moves. There are $\frac{4 !}{2 ! 2 !}$ ways to order those four steps and $2 !$ ways to determine the order of the remaining two steps, for a total of 12 sequences that we have to exclude. This gives $60-12=48$ sequences of steps. There are the same number of sequences for the steps N, N, E, E, E, W, so the probability here is $\frac{2 \times 48}{4^{6}}$.

The total probability is $\frac{6}{4^{4}}+\frac{96}{4^{6}}=\frac{3}{64}$, and $m+n=067$.

What is probability?

  • Probability is synonymous with possibility. It is a mathematical discipline that deals with the occurrence of a random event. The value ranges from zero to one.
  • Probability has been introduced in mathematics to predict the likelihood of occurrences occurring. Probability is defined as the degree to which something is likely to occur.
  • This is the fundamental probability theory, which is also utilized in probability distribution, in which you will learn about the possible results of a random experiment.
  • To determine the likelihood of a particular event occurring, we must first determine the total number of alternative possibilities.

To learn more about probability visit:

brainly.com/question/11234923

#SPJ4

4 0
2 years ago
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