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3 years ago

SOMEONE HELP!!!! WILL GIVE 50 POINTS AND BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!!!!!!

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

5 0

A is 7 4 and 3..B is the same...This is my first time with this kind of problem....

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You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the num

AnnyKZ [126]

Answer:

Step-by-step explanation:

d = number of dimes

2.80 = 0.1d + 0.25 (d + 8 )

2.80 = 0.1d + 0.25d + 2 Combine like terms

2.80 = 0.35d + 2 Subtract 2 from both sides

0.80 = 0.35d Divide both sides by 0.35

d ≈ 2.29

No, it's not possible to have more quarters than dimes when the total is $2.80 because it's not possible to have part of a dime.

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3 years ago

Help pLLEAAASSEE LOLOLOL

guajiro [1.7K]

Answer:

the answer is c, hope this helps

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3 years ago

Alison has three dogs but only two dog biscuits how can she divide them so that each dog get the same amount?

Lera25 [3.4K]

Each dog can get 2/3 of a dog biscuit.

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3 years ago

Read 2 more answers

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago

2.5x + 1.5 = 4x - 11 what is x

Alexeev081 [22]

Answer:

X = 8.3 (shortened)

<u>Steps for answer!</u>

1. Subtract 2.5x from both sides.

1.5=4x-11-2.5x

2. Simplify 4x-11-2.5 to 1.5x-11

1.5=1.5x-11

3. Add 11 to both sides.

1.5+11=1.5x

4. Simplify 1.5+11 to 12.5.

12.5=1.5x

5. Divide both sides by 1.5.

12.5/1.5=x

6. Simplify 12.5/1.5 to 8.3333338.333333.

8.333333=x

7. Switch sides.

x=8.333333

5 0

3 years ago