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Paraphin [41]
3 years ago
6

16 > -8 + x help me the homework is almost done!!

Mathematics
2 answers:
arlik [135]3 years ago
8 0

Answer:

24>x

Step-by-step explanation:

add 8 to both sides and the equation becomes 24>x

Pavel [41]3 years ago
6 0

Answer:

x < 24

Step-by-step explanation:

If ur looking to solve for x that would be ur answer

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Which statement is true about the diagram shown?
harina [27]

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I believe A is the correct answer.

Step-by-step explanation:

8 0
3 years ago
Enter the numerator that makes the equation true.
Gelneren [198K]

Answer:

1 3/4

Step-by-step explanation:

First write the equation in mixed fraction form as;

1 3/4 + 1 1/3 = 1 _/12 + 1 4/12 ⇒  7/4  + 4/3 = _ + 16/12

7/4  + 4/3 = _ + 16/12

37/12 = _ + 16/12

37/12 - 16/12 = _

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6 0
3 years ago
What are the original substances called in a chemical reaction?
yulyashka [42]

Answer:

reactants

A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).
Serjik [45]

Answer:

\displaystyle f(x)=x^2+2x+2

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

\displaystyle f(x)=ax^2+bx+c

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

\displaystyle f(-1)=a(-1)^2+b(-1)+c

\displaystyle f(-1)=a-b+c

\displaystyle a-b+c=1.....[eq\ 1]

Now we use the second condition f(1)=5

\displaystyle f(1)=a(1)^2+b(1)+c

\displaystyle f(1)=a+b+c

\displaystyle a+b+c=5.......[eq\ 2]

Finally, we use the third condition f(2)=10

\displaystyle f(2)=a(2)^2+b(2)+c

\displaystyle f(2)=4a+2b+c

\displaystyle 4a+2b+c=10....[eq\ 3]

We put together eq 1, eq 2, and eq 3 to form the system

\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.

Adding the first two equations we have

\displaystyle 2a+2c=6

\displaystyle a+c=3

And also

\displaystyle b=2

Using the above equation and the value of b in the third equation, we have

\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.

Subtracting the first equation from the second

\displaystyle 3a=3

\displaystyle a=1

And therefore

\displaystyle c=2

Now we have all the values, the quadratic function is

\displaystyle \boxed{f(x)=x^2+2x+2}

6 0
3 years ago
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