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goldfiish [28.3K]

3 years ago

6

All of the alkali metals, Group 1, have one valence electron. Which of these would represent the oxidation number of the alkali

metals such as lithium and sodium? A) -7 B) -1 C) +1 D) +7

1 answer:

Bond [772]3 years ago

6 0

The answer to this question is c

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Sunny_sXe [5.5K]

The test tube that first stops in bubbling or the production of a gas is the tube that contains the catalyst since the reaction ended faster than the others. A catalyst is known to speed up a reaction so it must the situation aforementioned is the answer.

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3 years ago

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It takes 3.3 j of work to stretch a hooke's-law spring 15 cm from its unstressed length. how much the extra work is required to

Likurg_2 [28]

5.786j

Set up a proportion. Add 11.3 and 15=26.3cm.
Next, the proportion of 3.3j/15cm=×/26.3cm

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3 years ago

A truck traveling at a constant speed of 40.0 km/h applies its brakes and comes to a complete stop in 5.0 s.

I am Lyosha [343]

Answer:

Part a)

$v = 11.11 m/s$

Part c)

$a = -2.22 m/s^2$

This mean the truck is decelerating and its speed is decreasing

Part e)

$t = 13.89 s$

Part f)

$d = 77.14 m$

Explanation:

Part a)

Speed of the truck is given as

$v = 40 km/h$

as we know that

1 km = 1000 m

1 h = 3600 s

so we will have

$v =40 \times \frac{1000}{3600} m/s$

$v = 11.11 m/s$

Part c)

Average acceleration is given as

$a = \frac{v_f - v_i}{t}$

now we have

$a = \frac{0 - 11.11}{5}$

$a = -2.22 m/s^2$

Part e)

as we know that it is uniform acceleration

so we can say

$v_f - v_i = at$

$11.11 - 0 = 0.80 t$

$t = 13.89 s$

Part f)

distance traveled by the truck is given as

$d = \frac{1}{2}at^2$

$d = \frac{1}{2}(0.80)(13.89^2)$

$d = 77.14 m$

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3 years ago

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Answer:

When you lift the ball, you are doing work to increase its gravitational potential energy. When you then release the ball, gravitational energy is transformed into kinetic energy as the ball falls. When the ball hits the floor, the ball's shape changes as it flattens against the floor.

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