My calculator is about 1cm thick, 7cm wide, and 13cm long.
Its volume is (length) (width) (thick) = (13 x 7 x 1) = 91 cm³ .
The question wants me to assume that the density of my calculator
is about the same as the density of water. That doesn't seem right
to me. I could check it easily. All I have to do is put my calculator
into water, watch to see if sinks or floats, and how enthusiastically.
I won't do that. I'll accept the assumption.
If its density is actually 1 g/cm³, then its mass is about 91 grams.
The choices of answers confused me at first, until I realized that
the choices are actually 1g, 10² g, 10⁴ g, and 10⁶ g.
My result of 91 grams is about 100 grams ... about 10² grams.
Your results could be different.
Answer:
The speed of the laser light in the cable, 
Explanation:
It is given that,
Wavelength of Argon laser, 
Refractive index, n = 1.46
Let 
is the speed of the laser light in the cable. The speed of light in a medium is given by :
or
So, the speed of the laser light is 
. Hence, this is the required solution.
Answer:
laser's wavelength λ = 597.4 nm
Explanation:
Given:
Slit spacing, d = 1.17mm
Tenth bright fringe y = 4.57cm
Distance from slits, D = 8.95m
n = 10
λ = (d * y) / (D * n)
λ = (1.17x10⁻³ * 4.57x10⁻²) / (8.95 x 10)
λ = 5.3469x10⁻⁵ / 8.95x10¹
λ = 0.5974 x 10⁻⁵⁻¹
λ = 0.5974 x 10⁻⁶ m
λ = 597.4 x 10⁻⁹ m
λ = 597.4 nm
Answer:
Rifle Momentum=7.77kg*m/s v'= 1.554 m/s
Explanation:
a) m1v1 + m2v2 = m1v1' + m2v2'
0+0 = 0.03*259 + P(rifle momentum)
solve for P
p= 7.77kg*m/s
b) 7.77= 5*v'
v'= 1.554 m/s
The formula F=velocity/wavelength
F=24/2
F=12 Hz
