All categories

3 years ago

Can you please show me the working of 56 x 16 in a sum

Mathematics

1 answer:

miv72 [106K]3 years ago

7 0

Can you please show me the working of 56 x 16 in a sum?
56x16=896

You might be interested in

Evaluate -3- (-4) - (-2) + 1.

Shtirlitz [24]

Answer:

Step-by-step explanation:

-3+4+2+1=4

8 0

3 years ago

PLEASE HELP ASAP WILL MARK AS BRAINLYEST

Stolb23 [73]

Answer:

The answer is 40.

Step-by-step explanation:

4x5 for the square part.

2x10 for the rectangle part

add them

5 0

3 years ago

Read 2 more answers

Multiply.

Anvisha [2.4K]

Answer:

2x*x

2x*-5

1*x

1*-5

2x²-10x+x-10 add numbers that have similar variables

-2x²-10x+x-10

=[-2x²-9x-10]

8 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

Write an expression to represent the sum of three consecutive even numbers. Let C represent the first number in the series

Anna [14]

Let, the first number = C
second number will be = C + 2 ['cause next will be odd so we can't include that]
Third number = C + 4

Now, their sum would be:
C + C+2 + C+4 = 3C + 6

In short, Your Answer would be 3C + 6

Hope this helps!

7 0

3 years ago

Read 2 more answers