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Anastaziya [24]
3 years ago
8

Write an expression to represent the sum of three consecutive even numbers. Let C represent the first number in the series

Mathematics
2 answers:
Anna [14]3 years ago
7 0
Let, the first number = C
second number will be = C + 2   ['cause next will be odd so we can't include that]
Third number = C + 4

Now, their sum would be:
C + C+2 + C+4 = 3C + 6

In short, Your Answer would be 3C + 6

Hope this helps!


vladimir2022 [97]3 years ago
7 0
Consecutive even integers would differ by 2.

So if the first even integer is C,

The next is C + 2

The next after is C + 2 + 2 = C + 4

The sum of the three consecutive integers =  C + (C + 2) + (C + 4)

 C + C + 2 + C + 4

C + C + C + 2 + 4

3C + 6

Sum = 3C + 6

Hope this helps.
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Sandra throws an object straight up into the air with an initial velocity of 38 ft/s from a platform that is 30 ft above the gro
Makovka662 [10]

Answer:

The answer is C.

Step-by-step explanation:

Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.

In this case, the initial postion is a platform 30ft above ground so h0=+30

The initial velocity is 38 ft/s straight up into the air so v0=+38

h(t)=-16t2+38t+30

When the object hits the ground, h=0.

h=-16t2+38t+30=0

Simplifying 8t2-19t-15=0

(8t+5)(t-3)=0

t=-5/8 or 3

As time cannot be -ve, t=3s. The answer is C.

6 0
2 years ago
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Which ordered pair is a solution to the equation? y=x3/4
Leni [432]

Answer:

(8,6)

Step-by-step explanation:

y=x3/4

y=8(3/4)

y=24/4

y=6

when you input 8 for x, you get 6 for y.

6 0
3 years ago
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*Please Help!* (Easy question) 20 POINTS
mariarad [96]
Yes - they have to be similar.  Since they are using the same line as the hypotenuse, the ratio of the other two sides are in the same ratio (ie, the slope of the line), the 3 inner angles will be the same.  Thus, the triangles will be similar.
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2 years ago
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Which of the following equations is equivalent to the equation 6x-y=1
kondaur [170]
A. 6x-y=1 can go to 6x-y-1=0 and then 6x-1 = y 
3 0
3 years ago
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To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
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