Write an expression to represent the sum of three consecutive even numbers. Let C represent the first number in the series
2 answers:
Let, the first number = C
second number will be = C + 2 ['cause next will be odd so we can't include that]
Third number = C + 4
Now, their sum would be:
C + C+2 + C+4 = 3C + 6
In short, Your Answer would be 3C + 6
Hope this helps!
Consecutive even integers would differ by 2.
So if the first even integer is C,
The next is C + 2
The next after is C + 2 + 2 = C + 4
The sum of the three consecutive integers = C + (C + 2) + (C + 4)
C + C + 2 + C + 4
C + C + C + 2 + 4
3C + 6
Sum = 3C + 6
Hope this helps.
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Answer:
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Step-by-step explanation:
ax=bx+1
Subtract by bx on both sides
ax-bx=1
x(a-b)=1
x= 1/(a-b)
Answer:
3*7=21
6*7=42
so 3*7 is 1/2 of 6*7
Step-by-step explanation:
Answer:
-5f+6
Step-by-step explanation:
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15-9= 6
Answer is -5f+6
Hope this helps!
-1 is greater then 1.05 then 1.05 then 1.55
so the answer is C