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natima [27]
3 years ago
13

Evaluate the piecewise function at the indicated value from the domain: f(x)=[1/x, if x<-2 x^2, if x> with the equal sign

on the bottom -2 at x=-3
A) f(-3)=4
B) f(-3)=9
C) (-3)= -1/3
D) f(-3)= -1/2
Mathematics
2 answers:
Katen [24]3 years ago
7 0

Answer:

C. f(-3)=\dfrac{-1}{3}

Step-by-step explanation:

We are given the piecewise function as follows

f(x)=\left\{\begin{matrix}\dfrac{1}{x}, &x

It is required to find the value of f(-3).

Since, we know that -3 < -2.

So, the function corresponding to x= -3 is given by,

f(x)=\dfrac{1}{x}.

Thus, we get,

f(-3)=\dfrac{1}{-3}=\dfrac{-1}{3}

Hence, option C is correct.

9966 [12]3 years ago
4 0
The answer is B. I hope I've helped you.
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2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


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