Answer:
5 4/5
Step-by-step explanation:
First of all subtract the whole number, 2, from 8 1/5
You would get 6 1/5
Now subtract 2/5 from that, or set up an equation like:
6 + 1/5 - 2/5
you would get 6 - 1/5 or 5 4/5
-Chetan K
Answer:
23:44 or 1:1.91
Step-by-step explanation:
w:l =69:132 Divide each number by 3
= 23:44 Divide each number by 23
≈ 1:1.91
The width-to-length ratio is 23:44 or approximately 1:1.91
Answer:
19.7
Step-by-step explanation:
37-17.3=19.7 which would be the value of x
He is 174 yards from the top.
Since we have a 60° angle and a right angle, this is a 30-60-90 triangle. In these triangles, we can label the sides as t, t√3 and 2t, with t being the side opposite the 30° angle (the smallest side); t√3 being the side opposite the 60° angle (the middle side); and 2t being the hypotenuse (the longest side).
Our 87 yard side is across from the 30° angle, so it is t.
The side we are looking for is the hypotenuse, which would be 2t; 2(87) = 174.
Answer:
Step-by-step explanation:
Hello!
X: Cholesterol level of a woman aged 30-39. (mg/dl)
This variable has an approximately normal distribution with mean μ= 190.14 mg/dl
1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:
P(Z≥z₀)= 0.093
-*or*-
P(Z≤z₀)= 0.907
Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:
P(Z≤z₀)= 0.907
Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:
z₀= 1.323
2.
Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:
Z= (X- μ)/δ ~N(0;1)
Z= (X- μ)/δ
Z*δ= X- μ
δ=(X- μ)/Z
δ=(240-190.14)/1.323
δ= 37.687 ≅ 37.7 mg/dl
I hope it helps!
