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2 years ago

A housepainter mixed 5 gal of blue paint with every 9 gal of yellow paint in order to make a

Mathematics

2 answers:

NikAS [45]2 years ago

8 0

I think any of these would work

10;18

15;28

20;35

Rudiy272 years ago

8 0

Answer:

5:9

Step-by-step explanation:

To Find:

ratio of yellow paint to blue paint to make a particular shade of green.

Solution:

The ratio can be written as 5 to 9, or 5:9

We know that if we mix 5 gallons of blue paint with 9 gallons of yellow paint we get the particular shade of green that we want.

Then the ratio of gallons of blue paint to gallons of yellow paint is 5 to 9, or 5:9

Meaning that for every 5 gallons of blue paint we need 9 of yellow paint.

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Ella has a points card for a movie theater.

MAXImum [283]

Answer:

175<=12.5x+40

Step-by-step explanation:

She starts with 40 points already so you add in those 40 then since she gets 12.5 points per visit that is your x, so you set that as greater than or equal to 175

7 0

2 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

3 years ago

How many numbers of possible live card hands (hands in five-card poker) drawn without replacement from a standard deck of 52 pla

makkiz [27]

The combination shows that the numbers of possible live card hands drawn without replacement from a standard deck of 52 playing cards is 2,598,960.

<h3>How to explain the information?</h3>

A permutation is the act of arranging the objects or numbers in order while combinations are the way of selecting the objects from a group of objects or collection such that the order of the objects does not matter.

Since the order does not matter, it means that each hand is a combination of five cards from a total of 52.

We use the formula for combinations and see that there are a total number of C( 52, 5 ) = 2,598,960 possible hands.

Learn more about permutations and combination on:

brainly.com/question/4658834

#SPJ1

3 0

1 year ago

a taxi begins at 4,-3 it travels 3 blocks west and 5 blocks north to pick up a customer. what are the customers coordinates

Flauer [41]

1, 2

will be the customers cordinate

8 0

3 years ago