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Gnesinka [82]
3 years ago
11

Resolver la ecuación trigonometrica: Senx^2=Cosx^2-Senx

Mathematics
1 answer:
Arisa [49]3 years ago
8 0
I would help but I don't speak your language do u speak English not being mean
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Need An Answer ASAP ... THANK YOU !!!
lozanna [386]

Answer:

∠EFG = 48°

Step-by-step explanation:

As FH bisects ∠EFG , ∠EFH = ∠HFG .

We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°

Also, ∠HFG  + ∠EFH = ∠EFG

=> 2(-5x + 89)° = (61 - x)°

=> -10x + 178 = 61 - x

=> 10x - x = 178 - 61

=> 9x = 117

=> x = 117 / 9 = 13

Putting the value of 'x' in ∠EFG gives :-

(61 - x)° = (61 - 13)° = 48°

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