6.8 is the pH of the solution after 10 ml of 5M NaOH is added.
Explanation:
Data given:
Molarity of C6H5CCOH = 0.100 M
molarity of ca(c6h5coo)2 = 0.2 M
Ka = 6.3 x 10^-5
first pH is calculated of the buffer solution
pH = pKa+ log 10 ![\frac{[A-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D)
pKa = -log10[Ka]
pka = -log[6.3 x10^-5]
pKa = 4.200
putting the values to know pH of the buffer
pH = 4.200 + log 10 
pH = 4.200 + 0.3
pH = 4.5 (when NaOH was not added, this is pH of buffer solution)
now the molarity of the solution is calculated after NaOH i.e Mbuffer is added
MbufferVbuffer = Mbase Vbase
putting the values in above equation:
Mbuffer = 
= 
= 0.01 M
molarity or [ A-] = 5M
pH = pKa+ log 10 ![\frac{[A-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D)
pH = 4.200 + log 10 
pH = 4.200+ 2.69
pH = 6.8
They vibrate back and forth
Answer:
hydrogen bonds between water molecules
Explanation:
The hydrogen bonds between water molecules conditions the bulk of its physical property most especially its relatively high boiling point. The hydrogen bond results from the attraction between the oxygen of a water molecule and the hydrogen of another water molecule. The more electronegative oxygen atom causes a distortion and the attraction leads to a strong intermolecular bond between atoms of the water molecules.
Hydrogen bond is a very strong bond and it is responsible for the physical properties of water.
I believe the answer is A. Iron