Answer:
The molar solubility of SrCO3 will be lower in 0.10 M 0 M Sr(NO3)2 because of Sr2+
Explanation:
The question reflects the phenomenon known in chemistry as common ion effect. Common ion effect refers to the decreased solubility of a solid in a solution that contains an ion in common with the solute.
In the case of our example here, both strontium carbonate and strontium nitrate possess the strontium II ion in common. The presence of this ion in strontium nitrate will decrease the solubility of strontium carbonate in accordance with Le Chateliers principle. Hence the answer.
2.48 g/mL
Density = mass/volume = (205 g)/(82.5 mL) = 2.48 g/mL
Answer:
Option C, developmental view point
Explanation:
A person with preservationist viewpoint will think of only preserving the natural resources and the environment. While a person with a conservationist viewpoint will think of conserving the landscape, architecture, heritage, culture, buildings, rituals, etc.
However, a person with developmental viewpoint will think of developing resources at ease. He/She will prioritize development and comfort of customer above all.
Hence, option C is correct
16.94/18=.9411111
sig figs: 0.9411 mole of water
This problem is simply converting the concentration from molality to molarity. Molality has units of mol solute/kg solvent, while molarity has units of mol solute/L solution.
2.24 mol H2SO4/kg H2O * (0.25806 kg H2SO4/mol H2SO4) = 0.578 kg H2SO4/kg H2O
That means the solution weighs a total of 1 kg + 0.578 kg = 1.578 kg. Then, convert it to liters using the density data:
1.578 kg * (1000g / 1kg) * (1 mL/1.135 g) = 1390 mL or 1.39 L.
Hence, the molarity is
2.24/1.39 = 1.61 M
