All categories

3 years ago

Fossils are used to study

Chemistry

2 answers:

LiRa [457]3 years ago

6 0

Organism once lived

ololo11 [35]3 years ago

4 0

The answer is organisms that onced lived Brainly 2021

You might be interested in

What is the general formula for alkenes?<br> CnH2n-2<br> CnH₂n<br> CnH2n-1<br> CH 2n-2

Oksi-84 [34.3K]

Answer:

Alkenes have the general formula of $C_{n} H_{2n$ .

3 0

3 years ago

Read 2 more answers

In this reaction, what is the substance oxidized? zn(s) + 2 hcl(aq) → zncl2(aq) + h2(g) zinc chloride chlorine hydrogen zn oxyge

Zarrin [17]

Zn(s) + 2 HCl(aq) → ZnCl₂(aq) + H₂(g)
Oxidation means lose of electrons and increase of positive charge so the part which oxidized in this equation is Zn(s) because it converted to Zn²⁺ (i.e. lost two electrons)

7 0

4 years ago

Read 2 more answers

NEED ANSWER ASAP

Ber [7]

That would be Mutualism

8 0

3 years ago

Read 2 more answers

A hurricane is getting stronger if A the pressure in the eye is increasing B the pressure in the eye is remaining the same C the

user100 [1]

The answer would be A: THE PRESSURE IN THE EYE IS INCREASING.

HOPE THIS HELPS :)

4 0

3 years ago

A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 1

LuckyWell [14K]

Answer:

A compressed gas cylinder is filled with 5270 g of argon gas.

The pressure inside the cylinder is 2050 psi at a temperature of 18C.

The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.

How many grams of argon remains in the cylinder?

Explanation:

First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:

Mass of Ar gas is --- 5270g.

The number of moles of Ar gas:

$Number of moles of Ar gas=\frac{given mass of Ar}{its atomic mass} \\ =\frac{5270g}{39.948g/mol} \\ =131.9mol$

Temperature T=(18+273)K=291K

Pressure P=2050psi

$2050* 0.0680atm\\\\=139.4atm\\$

Volume V=?

$PV=nRT\\139.4atm * V=131.9mol *0.0821L.atm.mol-1.K-1 * 291K\\=>V=\frac{131.9mol *0.0821L.atm.mol-1.K-1 * 291K}{139.4atm} \\=>V=22.6L$

Using this volume V=22.6L

Pressure=650psi=44.2atm

Temperature T= (26+273)K=299K

calculate number of moles "n" value:

$PV=nRT\\=>n=\frac{PV}{RT} \\=>n=\frac{44.2atm*22.6L}{0.0821L.atm.mol^-1K^-1* 299K} \\=>n=40.7mol$

Mass of 40.7mol of Ar gas:

$mass of Ar gas=number of moles * its atomic mass\\\\ =40.7mol* 39.948g/mol\\\\ =1625.8g$

Answer:

The mass of Ar gas becomes 1625.8g.

8 0

3 years ago