Answer:2 (-2x + 4 - 5 - 3)
2(-2x -4)
-4x - 8
A the correct answer is a I hope you get it correct and your doing amazing !
<span>Seg BA is congr to seg BC and seg DA is cong to seg DC by given
Seg BD is congr to seg BD by reflexive
Tr. BAD is congr to tr. BCD by SSS</span>
The team has played 24 home games.
Let h be the number of home games and a be the number of away games. The total number of games is 49; this gives us
h+a=49
They won 2/3 of the home games and 2/5 of the away games; there were 26 games won. This gives us
2/3h + 2/5a = 26
In the first equation we isolate h by subtracting a from both sides:
h+a-a=49-a
h=49-a
Substitute this into the second equation:
2/3(49-a)+2/5a = 26
Using the distributive property, we have
2/3*49 - 2/3*a + 2/5a = 26
98/3 - 2/3a + 2/5a = 26
Finding a common denominator to combine like terms, we have
98/3 - 10/15a + 6/15a = 26
98/3 - 4/15a = 26
We want to convert the whole number to thirds as well; 26 = 26*3/3 = 78/3:
98/3 - 4/15a = 78/3
Subtracting 98/3 from both sides:
98/3 - 4/15a - 98/3 = 78/3 - 98/3
-4/15a = -20/3
Divide both sides by -4/15:
a = -20/3 ÷ -4/15
a = -20/3 × - 15/4 = 300/12 = 25
There were 25 away games.
This means there were 49-25 = 24 home games.
Answer:X=110/121
Step-by-step explanation:
Multiply 100 by 1.21 then by x
121x=110
Divide both side by 121
X=110/121
X=0.91
