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SVETLANKA909090 [29]
3 years ago
8

If you spun the spinner 100 times, how many times do you predict that you would spin a number less than 5 on a spinner of 1-6

Mathematics
1 answer:
Roman55 [17]3 years ago
8 0

Answer:

67 times

Step-by-step explanation:

Spinner's sample space = (1, 2, 3, 4, 5, 6)

Number less than 5 = (1, 2, 3, 4)

Total possible outcomes = 6

Required outcome = 4

P(number less than 5) = required outcome / Total possible outcomes

P(number less than 5) = 4 /6 = 2/3

Number of spins = 100

Predicted Number of times a number less than less than 5 is spurn in 100 spins :

100 * 2/3

= 66.666

= 67 times

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Answer:

a = 3.5

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A stock market gains 83 points. The next day, the stock market loses 47 points.Write each amount as an interger
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4 years ago
The exponential function f(x) = 3(5)x grows by a factor of 25 between x = 1 and x = 3. What factor does it grow by between x = 5
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Answer:

B) 25

Step-by-step explanation:

Given exponential function:

f(x)=3(5)^x

The growth factor between x=1 and x=3 is 25.

To find the growth factor between x=5 and x=7

Solution:

The growth factor of an exponential function in the interval x=a and x=b is given by :

G=\frac{f(b)}{f(a)}

We can check this by plugging in the given points.

The growth factor between x=1 and x=3 would be calculated as:

G=\frac{f(3)}{f(1)}

f(3)=3(5)^3

f(1)=3(5)^1

Plugging in values.

G=\frac{3(5)^3}{3(5)^1}

G=\frac{(5)^3}{(5)^1} (On canceling the common terms)

G=(5)^{(3-1)}  (Using quotient property of exponents \frac{a^b}{a^c}=a^{(b-c)} )

G=(5)^{2}

∴ G=25  

Similarly the growth factor between x=5 and x=7 would be:

G=\frac{f(7)}{f(5)}

f(7)=3(5)^7

f(5)=3(5)^5

Plugging in values.

G=\frac{3(5)^7}{3(5)^5}

G=\frac{(5)^7}{(5)^5} (On canceling the common terms)

G=(5)^{(7-5)}  (Using quotient property of exponents \frac{a^b}{a^c}=a^{(b-c)} )

G=(5)^{2}

∴ G=25  

Thus, the growth factor remains the same which is  =25.

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3 years ago
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