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SashulF [63]
3 years ago
9

You have discovered your excel at community with people and understand whenever a person is being honest. Which career might you

choose ?
1) management
2)social work
3)interview
4)therapists
Chemistry
1 answer:
tatuchka [14]3 years ago
4 0
Therapists should be the right answer
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A mixture was found to contain 1.05g of SiO2, 0.69g of cellulose and 1.82g of calcium carbonate. What percentage of calcium carb
mihalych1998 [28]
1,05g+0,69g+1,82g=3,56g\\\\
3,56g \ \ \ \Rightarrow \ \ \ 100\%\\
1,82g \ \ \ \Rightarrow \ \ \ x\\\\
x=\frac{1,82g*100\%}{3,56g}\approx 51,12\%
5 0
3 years ago
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According to the wave- mechanical model of the atom , an orbital is a region of the most probable location of ? ( please provide
notka56 [123]
An orbital is the most probable location of an electron. This is because you can't pinpoint the exact location of an electron because as soon as you do it will have moved again, so orbitals are used to find the probability of where a certain electron is.
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4 years ago
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On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What
topjm [15]

Answer : The atomic mass of chlorine is, 36.723 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Mass of 35-Cl isotope = 35 amu

Percentage abundance of 35-Cl isotope = 13.85 %

Fractional abundance of 35-Cl isotope = 0.1385

Mass of 37-Cl isotope = 37 amu

Percentage abundance of 37-Cl isotope = 86.15 %

Fractional abundance of 37-Cl isotope = 0.8615

Now put all the given values in above formula, we get:

\text{Average atomic mass }=[(35\times 0.1385)+(37\times 0.8615)]

\text{Average atomic mass }=36.723amu

Therefore, the atomic mass of chlorine is, 36.723 amu

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4 years ago
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