Answer:
c and d are correct
Explanation:
In A, false because in Valence Electrons, the more the valences, the more stable an atom is.
In B, false because atoms cannot readily gain or lose valence electrons as the number of valence electrons is determined by the column they are in.
In C, true because the more the valence electrons, the more the stability of an atom.
In D, true as electron placing is important and the reactivity of an atom is important.
So C and D are true!
A locating agent is needed in an experiment to separate amino acids by chromatography as it helps to analyze colorless substances on paper.
<h3>What is chromatography?</h3>
Chromatography is an analytical method frequently used to separate a chemical mixture into its components, allowing for in-depth analysis of each component.
There are many different types of chromatography including liquid, gas, ion-exchange, and affinity chromatography, but they all use the same basic principle.
<h3>What is the use of a locating agent in Chromatography?</h3>
In paper chromatography, colorless compounds are examined using a locating agent.
It is a chemical that combines with colorless substances to produce colorful compounds that are easy to see for analysis. Ninhydrin spray is an example of a locating agent of this type.
Thus, a locating agent is used in an experiment to separate amino acids by chromatography as it helps in determining colorless substances on paper.
Learn more about chromatography:
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Answer:
280.8 g
Explanation:
Definimos la reaccion:
2NaOH + FeSO₄ → Na₂SO₄ + Fe(OH)₂
Como tenemos la masa de NaOH, asumimos que el sulfato de hierro (II) es el reactivo en exceso.
Definimos masa de reactivo: 250 g . 1mol / 40g = 6.25 mol
2 moles de NaOH producen 1 mol de hidroxido ferroso
Entonces 6.25 moles producirán, la mitad (6.25 . 1) /2 = 3.125 moles
Convertimos los moles a masa:
3.125 mol . 89.85 g/mol = 280.8 g
Answer:
do you mean?
Explanation:
the structural formula of butyl pentyl ether
Answer:
O₂; KCl; 33.3
Explanation:
We are given the moles of two reactants, so this is a limiting reactant problem.
We know that we will need moles, so, lets assemble all the data in one place.
2KCl + 3O₂ ⟶ 2KClO₃
n/mol: 100.0 100.0
1. Identify the limiting reactant
(a) Calculate the moles of KClO₃ that can be formed from each reactant
(i)From KCl
(ii) From O₂
O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.
KClO₃ is the excess reactant.
2. Moles of KCl left over
(a) Moles of KCl used
(b) Moles of KCl left over
n = 100.0 mol - 66.67 mol = 33.3 mol
