Can you show me how to do 246 divided by 6 in lesson 4.6 go math

X=number of corect
y=number of incorrect
5 points for each correct so 5x
-1 point for each incorrect so -y

5x-y=76
solve for x and y

I like putting it into slope intercep tofrm which is y=mx+b
add y to both sides
5x=76+y
subtract 76 from both sides
5x-75=y
y=5x-76

subsitute values for x and get values for y
remember, that julia cannot answer a negative number of incorrect questions so y must be greater than or equal to 0

so solve for minimum
0<5x-76
add 76 to both sides
76<5x
divide by 5
15.2<x
you cannot answer a fraction of a correct quesiton so round up
16 is the minumum number of queswtions correctlyh answered

so
x>16

subsitute 16 for x
y=5(16)-76
y=80-76
y=4

as we subsitute more numbers over 16, we get these points
so (x,y)
(16,4)
(17,9)
(18,14)
(19,19)
(20,24)
(21,29)
(22,34)
(23,39)
x=correct answer
y=wrong answers

5 0

3 years ago

Compute the loss of head and pressure drop in 200 ft of horizontal 6-in diameter asphalted cast iron pipe carrying water with a

laiz [17]

Answer:

The answer is below

Step-by-step explanation:

12 inches = 1 ft.

6 inches = 6 inches * (1 ft./12 inches) = 0.5 ft.

Therefore the diameter of the cast iron (D) = 6 inches = 0.5 ft.

The area of cast iron (A) = πD²/4 = π(0.5)²/4 = 0.196 ft²

The velocity (V) = 6 ft./s, the acceleration due to gravity (g) = 32.2 ft./s²

ε/D = 0.0004 ft./ 0.5 ft. = 0.0008

Using the moody chart, find the line ε/D = 0.0008 and determine the point of intersection with the vertical line R = 2.7 * 10⁵. Hence we get f = 0.02.

The head loss (h) is:

$h_f=f*\frac{L}{d}* \frac{V^2}{2g}=0.02*\frac{200\ ft}{0.5\ ft} *\frac{(6\ ft/s)^2}{2*32.2\ ft/s^2}=4.5\ ft$

The pressure drop (Δp) is:

Δp = ρg $h_f$ = $(62.4\ lbf/ft^3)(4.5\ ft)= 280\ lbf/ft^2$

5 0

3 years ago

Judy’s brother Sam has a collection of 96 comic books what are the 10 where is Sam could divide his comic books into equal group

sweet-ann [11.9K]

We have been given that Judy’s brother Sam has a collection of 96 comic books. We have been asked to find the 10 ways Sam could divide his comic books into equal groups.

This can be done as follows:

96 can be written as $2\times 48=48\times 2=96$ . Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.

Likewise, 96 can also be written as $3\times 32=32\times 3=96$ . Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.

Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.

Our question has been answered.

5 0

3 years ago