Can you show me how to do 246 divided by 6 in lesson 4.6 go math

PLZ help me!!!! I have no idea how to do this!

sp2606 [1]

Answer:

a) $y^b z^{(b-1)}$

Step-by-step explanation:

Hope this helps :)

7 0

3 years ago

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A regular octagon has a radius of 6 ft and a side length of 4.6 ft. what is the approximate area of the octagon? 71 ft2 101 ft2

Zielflug [23.3K]

The answer is 101 ft^2

3 0

3 years ago

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ANSWER PLEASE Tyler deposits $2000 and has a 8% interest compound quarterly. How much does he have Quarter 1,2,3,4 Show Work

guajiro [1.7K]

Answer:

If the time passed is only 3 months, then it is $2040

Step-by-step explanation:

We can use the quarterly compounded interest equation for this problem: P(1 + r/n)^nt

Step 1: Find out how much 3 months is in a year

<em>In this case, 3/12 which is 1/4</em>

Step 2: Plug in known variables into equation

2000[1 + (0.08)/4)]^[(4)(1/4)]

Step 3: Solve/Plug in calc

You will get $2040

If the time passed in the problem is 1 year, then we can be able to solve how much money he earned per quarter. However, since only 3 months have elapsed, then he has only earned $2040.

7 0

3 years ago

Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M’N’O’P’Q’.

N76 [4]

Answer:
slope of M'N' = 1

Explanation:
First, we will need to get the coordinates of points M' and N':
We are given that the dilation factor (k) is 0.8
Therefore:
For point M':
x coordinate of M' = k * x coordinate of M
x coordinate of M' = 0.8 * 2 = 1.6
y coordinate of M' = k * y coordinate of M
y coordinate of M' = 0.8 * 4 = 3.2
Therefore, coordinates of M' are (1.6 , 3.2)

For point N':
x coordinate of N' = k * x coordinate of N
x coordinate of N' = 0.8 * 3 = 2.4
y coordinate of N' = k * y coordinate of N
y coordinate of N' = 0.8 * 5 = 4
Therefore, coordinates of M' are (2.4 , 4)

Then, we can get the slope of M'N':
slope = (y2-y1) / (x2-x1)
For M'N':
slope = (3.2-4) / (1.6-2.4)
slope = 1

Hope this helps :)

8 0

3 years ago

Enter the slope-intercept equation for the image of line ℓ after a clockwise rotation of 90°. (Hint: To find the image of line ℓ

Free_Kalibri [48]

Answer:

y = -2x - 2

Step-by-step explanation:

From the graph attached,

If the line 'l' passes through two points A(0, -1) and B(4, 1).

Rule for the rotation of any point (x, y), 90° clockwise about the origin is,

(x, y) → (y, -x)

By this rule,

A(0, -1) → A'(-1, 0)

B(4, 1) → B'(1, -4)

Let the equation of the line A'B' is,

y - y' = m(x - x')

where m = slope of the line A'B'

And (x', y') is a point lying on the line.

Slope of the line passing through A' and B' will be,

m = $\frac{y_2-y_1}{x_2-x_1}$

m = $\frac{0+4}{-1-1}$

m = -2

Therefore, equation of the line passing through (-1, 0) and slope = -2,

y - 0 = (-2)(x + 1)

y = -2x - 2

So the equation of the line after rotation of lie 'l' by 90° clockwise will be,

y = -2x - 2

7 0

3 years ago