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Gnom [1K]
3 years ago
14

1. I am in group two period three. What element am I? A Ti B, C C. Ca D. WE

Chemistry
2 answers:
disa [49]3 years ago
6 0
It is magnesium (mg) but that is not a answer choice, so I would go with Ca since that’s in group 2
AysviL [449]3 years ago
5 0

Answer:

Ca

Explanation:

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In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl 2 solution:
4vir4ik [10]

Answer:

d

Explanation:

higher no of particles are in CaCl2 solution

4 0
2 years ago
The town of Eatonville has decided to replace all of the incandescent light bulbs in their public buildings with more energy-eff
astraxan [27]

Answer:A

Explanation:becuse they waste less heat energy

6 0
2 years ago
If 2.68 g of benzaldehyde are involved with the mixed aldol condensation reaction, how many moles of benzaldehyde are present? R
Zielflug [23.3K]

Answer:

The number of moles of benzaldehyde = 0.0253 moles

Explanation:

The molecular formula of benzaldehyde is C₇H₆O

Its molecular mass is calculated from the atomic masses of the constituent atoms.

C = 12.0 g: H = 1.0 g; O = 16.0 g

Molecular mass = ( 12 * 7) + (1 * 6) + (16 * 1) = 106.0 g/mol

Number of moles of  substance = mass of substance/ molar mass of the substance

mass of benzaldehyde = 2.68; molar mass = 106.0 g/mol

Number of moles of benzaldehyde = 2.68 g/ 106 g/mol = 0.0253 moles

Therefore, the number of moles of benzaldehyde = 0.0253 moles

8 0
3 years ago
Dry ice is solid carbon dioxide. Instead of melting, solid carbon dioxide sublimes according to the following equation: CO2(s)→C
GREYUIT [131]

Answer:

m=8.79kg

Explanation:

First of all we need to calculate the heat that the water in the cooler is able to release:

Q=\rho * V*Cp*\Delta T

Where:

  • Cp is the mass heat capacity of water
  • V is the volume
  • \rho is the density

Q=1 g/cm^3 *15000 cm^3*4.184 \frac{J}{g*^{\circ}C}*(10-90)^{\circ}C

Q=-5020800 J=-5020.8 kJ

To calculate the mass of CO2 that sublimes:

-Q=\Delta H_{sub}*m

Knowing that the enthalpy of sublimation for the CO2 is: \Delta H_{sub}=571 kJ/kg

5020.8 kJ=571 kJ/kg*m

m=\frac{5020.8 kJ}{571 kJ/kg}=8.79kg

6 0
3 years ago
The metal zirconium becomes superconducting at temperatures below 3.4000K.
dybincka [34]

Answer:

-269.75 degrees Celsius

Explanation:

7 0
3 years ago
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