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Alchen [17]
2 years ago
10

In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl 2 solution:

Chemistry
1 answer:
4vir4ik [10]2 years ago
4 0

Answer:

d

Explanation:

higher no of particles are in CaCl2 solution

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Which type of bond will most likely be found in HBr?
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How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
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What is the uses of plastic?
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What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
german
When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

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n is the moles' number (which we need to calculate)

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and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

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7 0
3 years ago
6) A 0.20 ml CO2 bubble in a cake batter is at 27°C. In the oven it gets
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Answer: The new volume of cake is 1.31 mL.

Explanation:

Given: V_{1} = 0.20 mL,         T_{1} = 27^{o}C

V_{2} = ?,                    T_{2} = 177^{o}C

Formula used to calculate new volume is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.20 mL}{27^{o}C} = \frac{V_{2}}{177^{o}C}\\V_{2} = 1.31 mL

Thus, we can conclude that the new volume of cake is 1.31 mL.

5 0
3 years ago
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