Answer:
0.203 is the mean of the concentration of the HCl solution
Explanation:
You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:
0.210 + 0.204 + 0.201 + 0.202 + 0.197 = 1.014 / 5 =
<h3>0.203 is the mean of the concentration of the HCl solution</h3>
Based on the chemical equation, to balance the given equation we should use 2 as a coefficients of HCl on reacatnt side of the reaction.
<h3>What is balanced equation?</h3>
Balanced chemical equations are those equation in which each entities are present in same amount on reactant side as well as on the product side of the chemical reaction.
Given chemical reaction is:
Zn + HCl → ZnCl₂ + H₂
In the above reaction equation is not balanced as number of chlorine and hydrogen atoms are not equal on both sides, so balanced equation will be:
Zn + 2HCl → ZnCl₂ + H₂
Hence we add 2 as a coefficient of HCl to balance the equation.
To know more about balance equation, visit the below link:
brainly.com/question/15355912
Answer chocies .......................
Answer:
A. Polar Easterlies
B. Westerlies
C. Northeast Trades
D. Southeast Trades
E. Westerlies
F. Polar Easterlies
G. Hadley cell
Explanation:
I am pretty sure this is right. Hope that helps
<h3><u>Answer</u>;</h3>
a. 3 molecules 3 carbon
b. 6 molecules 18 carbon
c. 6 molecules 18 carbon
d. 5 molecules 15 carbon
e. 3 molecules 15 carbon
f. 3 molecules 15 carbon
<h3><u>Explanation</u>;</h3>
- In the Calvin cycle, carbon atoms from CO2 are ncorporated into organic molecules and then used to build three-carbon sugars, a process that is fueled by, and dependent on, ATP and NADPH from the light reactions.
- Calvin cycle take place in the stroma. Reactions of Calvin cycle are divided into three main stages: carbon fixation, reduction, and regeneration of the starting molecule.
- During carbon fixation, a CO2 molecule combines with a five carbon acceptor molecule ribulose-1,5-bisphosphate. The result is a six carbon compound that splits to two three carbon compound, 3-PGA.
- During reduction; ATP and NADPH are used to convert the 3-PGA molecules into molecules of a three-carbon sugar, glyceraldehyde-3-phosphate.
- Finally during regeneration, some G3P molecules are used to make glucose while others are recycled to regenerate RuBP acceptor.
