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3 years ago

A solid object has a mass of 30 grams and a volume of 10 cm3.

2 answers:

german3 years ago

7 0

To find the density of an object, you need to use the equation: D = M/V. This is density equals mass over volume.

Mass: 30 g
Volume: 10 cm3

30/10 = 3

Density: 3 g/cm3

tresset_1 [31]3 years ago

6 0

Answer: The density of the object is equal to $3g/cm^3$

Explanation:

Density of an object is defined as the ratio of its mass and volume. The chemical equation representing density of an object is:

$\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}$

We are given:

Mass of an object = 30 grams

Volume of an object = $10cm^3$

Putting values in above equation, we get:

$\text{Density of an object}=\frac{30g}{10cm^3}=3g/cm^3$

Hence, the density of the object is equal to $3g/cm^3$

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The table below shows the electronegativity values of various elements on the periodic table. Electronegativities A partial peri

MatroZZZ [7]

Answer:

Oxygen and Chlorine

Explanation:

Covalent bonds involve the sharing of electrons between nonmetals.

4 0

4 years ago

Read 2 more answers

What is the molarity of 5.74 liters of solution made with 246 grams of iron (III) chloride (FeCl3)? Answer with 3 SDs.

geniusboy [140]

Answer:

0.264 mol/L

Explanation:

Data obtained from the question includes:

Volume = 5.74L

Mass of FeCl3 = 246 g

Molarity =?

Next, we shall determine the number of mole in 246g of FeCl3.

This is illustrated below:

Mass of FeCl3 = 246g

Molar mass of FeCl3 = 56 + (35.5x3) = 162.5g/mol

Number of mole of FeCl3 =..?

Mole = Mass /Molar Mass

Number of mole of FeCl3 = 246/162.5

Number of mole of FeCl3 = 1.514 mol

Now, we can obtain the molarity of the solution as follow:

Molarity = mole /Volume

Volume = 5.74L

Mole of FeCl3 = 1.514 mol

Molarity = 1.514/5.74

Molarity = 0.264 mol/L

5 0

3 years ago

Why ie of nobel gases are very high

zavuch27 [327]

Answer:

noble gases are very high because they have the maxium amount of electrons in their outer shell

Explanation:

4 0

3 years ago

if the column of water in the water barometer rose to a height of 33 feet, what would the atmospheric pressure be in mm Hg?

frez [133]

The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity. It can be calculated as follows:

P = density x g x h
P = 1000 kg/m^3 x 9.8 m / s x 33 ft x 0.3048 m/ft
P = 98572.32 kg/m^2

Hope this answers the question. Have a nice day.

5 0

3 years ago

How many atoms of N are in 137.0 grams of N2O3?

lara [203]

Answer: Option (d) is the correct answer.

Explanation:

It is given that mass of $N_{2}O_{3}$ is 137.0 g.

Molar mass of $N_{2}O_{3}$ is as follows.

Molar mass of $N_{2}O_{3}$ = 2 × 14 + 3 × 16

= 76 g

Thus, number of moles will be calculated as follows.

No. of moles = $\frac{mass}{molar mass}$

= $\frac{137.0 g}{76 g/mol}$

= 1.803 mol

There are 2 nitrogen (N) atoms present in the formula of dinitrogen trioxide. Also Avogadro's number equals $6.022 \times 10^{23}$ atoms or molecules per mol.

Therefore, number of N molecules or atoms in $N_{2}O_{3}$ is as follows.

Number of N atoms = $2 \times 1.803 mol \times 6.022 \times 10^{23} atoms/mol$

= $2 \times 10.855 \times 10^{23}$ atoms

= $2.171 \times 10^{24}$ atoms

Thus, we can conclude that there are $2.171 \times 10^{24}$ atoms of N in in 137.0 grams of $N_{2}O_{3}$ .

6 0

3 years ago