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3 years ago

A solid object has a mass of 30 grams and a volume of 10 cm3.

2 answers:

german3 years ago

7 0

To find the density of an object, you need to use the equation: D = M/V. This is density equals mass over volume.

Mass: 30 g
Volume: 10 cm3

30/10 = 3

Density: 3 g/cm3

tresset_1 [31]3 years ago

6 0

<u>Answer:</u> The density of the object is equal to $3g/cm^3$

<u>Explanation:</u>

Density of an object is defined as the ratio of its mass and volume. The chemical equation representing density of an object is:

$\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}$

We are given:

Mass of an object = 30 grams

Volume of an object = $10cm^3$

Putting values in above equation, we get:

$\text{Density of an object}=\frac{30g}{10cm^3}=3g/cm^3$

Hence, the density of the object is equal to $3g/cm^3$

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Charra [1.4K]

Answer:

The answer is A, B and E

Explanation:

A - carbohydrates

B - Lipids

C- COH

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all except O and NaOH

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3 years ago

What's the correct answer

svp [43]

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3 years ago

Calculate the equilibrium number of vacancies per cubic meter for copper at 1000K. The energy for vacancy formation is 0.9eV/ato

nexus9112 [7]

Answer:

Therefore the equilibrium number of vacancies per unit cubic meter =2.34×10²⁴ vacancies/ mole

Explanation:

The equilibrium number of of vacancies is denoted by $N_v$ .

It is depends on

total no. of atomic number(N)
energy required for vacancy
Boltzmann's constant (k)= 8.62×10⁻⁵ev K⁻¹
temperature (T).

$N_v=Ne^{-\frac{Q_v}{kT} }$

To find equilibrium number of of vacancies we have find N.

$N=\frac{N_A\ \rho}{A_{cu}}$

Here ρ= 8.45 g/cm³ =8.45 ×10⁶m³

$N_A$ = Avogadro Number = 6.023×10²³

$A_{Cu}$ = 63.5 g/mole

$N=\frac{6.023\times 10^{23}\times 8.45\times 10^{6}}{63.5}$

$=8.01\times 10^{28$ g/mole

Here $Q_v$ =0.9 ev/atom , T= 1000k

Therefore the equilibrium number of vacancies per unit cubic meter,

$N_v=( 8.01\times 10^{28}) e^{-(\frac{0.9}{8.62\times10^{-5}\times 1000})$

=2.34×10²⁴ vacancies/ mole

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3 years ago

True or False: As the ice warms up, the molecules get more energy and move around more from place to place to form liquid water.

Arada [10]

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Hope it helps.

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3 years ago

Read 2 more answers

You wish to construct a buffer of pH=7.0. Which of the following weak acids (w/ corresponding conjugate base) would you select?

Alex17521 [72]

Answer:

C.) HOCl Ka=3.5x10^-8

Explanation:

In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below

we Know that

pKa= -log(Ka)

therefore

A) pKa of HClO2 = -log(1.2 x 10^-2)

=1.9208

B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644

C) pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45

D) pKa of HCN = -log(4 x 1 0^-10)= 9.3979

If we consider the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution

The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.

So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.

Hence, HOCl will be chosen for buffer construction.

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3 years ago