Answer:
1646/1
Step-by-step explanation:
To write 1646 as a fraction you have to write 1646 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
1646 = 1646/1 = 16460/10
Given:
Consider the equation is:

To prove:
by using the properties of logarithms.
Solution:
We have,

Taking left hand side (LHS), we get

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

Hence proved.
5 (3m+2p) -4m= 15m +10p -4m
=11m +10p
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13p+11m-3p=10p -11m
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Yes, 5 (3m+2p) -4m is equivalent to the expression 13p+11m-3p as i worked out for you.. Hope this helps you!!! =')
Step-by-step explanation:
L.H.S=(1-cosB)(1+cosB)
=(1-cos^2B). {using (a+b) (a-b)=(a^2-b^2)in second step}
=sin^2B
=1/cosec^2B
Therefore,L.H.S=R.H.S proved
The answer is the first data set because remember, an outlier is a number in a data set that is extremely far away from all of the other numbers.
You can easily tell which one is the outlier, the first data set's outlier is 13, because it is was placed so far away from the other data points.
We know that the first data set is correct because all of the other data sets have numbers that are clustered together.
~Hope I helped!~