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antoniya [11.8K]
3 years ago
11

What happens during the process of composing functions?

Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0
<h2>Explanation:</h2>

By composing functions, we apply one function to the result of another function. So the definition is as follows:

The \ \mathbf{composition} \ of \ the \ function \ f \ with \ the \ function \ g \ is:\\ \\ (f \circ g)(x)=f(g(x))

Therefore, what happens during the process of composing functions is that:

The \ domain \ of \ (f \circ g) \ is \ the \ set \ of \ all \ x \ in \ the \ domain \ of \ g \\ such \ that \ g(x) \ is \ in \ the \ domain \ of \ f

In other words, we send the result of g() through the result of f()

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Hannah read a total of 798 pages over 6 hours. After a total of 36 hours of reading this week, how many pages will Hannah have r
Vika [28.1K]

Answer: 4788 pages

Step-by-step explanation:

798/6 hours

798 divided by 6 equals 133. Meaning Hannah read 133 pages in 1 hour. So divide the unit rate by 36. 133 x 36 = 4788 pages in 36 hours.  

6 0
3 years ago
-3.5 + x7= -5.2<br><br><br> pls answer
noname [10]
X=-17/70

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8 0
3 years ago
Find the measure of DC if m
kupik [55]

Answer:

  • B. 132°

Step-by-step explanation:

<u>Find the measure of arc BD</u>

  • m∠A = 1/2(arc BC - arc BD)
  • 2*36° = 150° - arc BD
  • arc BD = 150° - 72° = 78°

<u>Find the measure of arc DC</u>

  • arc BD + arc BC + arc DC = 360°
  • arc DC = 360° - (150° + 78°) = 360° - 228° = 132°

Correct choice is B

7 0
3 years ago
The actual length of side t is 0.045 cm. Use the scale drawing to find the actual side length of w. A) 0.06 cm B) 0.075 cm C) 0.
Tems11 [23]

Answer: The answer is B 0.075 cm


Step-by-step explanation:

Since the drawings is a scale of the original you must use a proportion to solve the desired side. 0.045/.9=w/1.5;w=0.075.

5 0
3 years ago
Read 2 more answers
Please help with this
snow_lady [41]

Answer:

B. -  \frac{9}{8}

Step-by-step explanation:

\huge\frac{ - 2 {a}^{ - 3} {b}^{2}  }{a}  \\  \\ \huge  =  \frac{ - 2  {b}^{2}  }{a \times{a}^{ 3} }   \\  \\ \huge =  \frac{ - 2  {b}^{2}  }{{a}^{ 4} }   \\  \\  \huge =  \frac{ - 2 \times  {3}^{2} }{ {( - 2)}^{4} }  \\  \\   \huge=  \frac{ - 2 \times 9}{16}  \\  \\  \huge  \red{=  -  \frac{9}{8} }

8 0
3 years ago
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