Divide use partial quotients 28 divided by 514

Denise is checking to determine if the expressions x+x+6 and 4+3x-2 are equivalent. When x=4, she correctly found that both expr

gayaneshka [121]

The answer would be 8 when the value of x = 2

3 0

4 years ago

Read 2 more answers

When 43,55 and 67 are divided by a certain number, the remainder is 7 in each case. Find the number?

siniylev [52]

Answer:

12

Step-by-step explanation:

First subtract 7 from 43, 55 and 67

43 - 7 = 36 ; 55 - 7 = 48 ; 67 - 7 = 60

Now find the GCF of 36 , 48 , 60

36 = 2 * 2 * 3 * 3

48 = 2 * 2 * *2*2 * 3

60 = 2 * 2 * 3 * 5

GCF = 2 * 2 * 3 = 12

The required number is 12

When you divide 43 by 12, the remainder is 7.

When you divide 55 by 12, the remainder is 7

When you divide 67 by 12, the remainder is 7

5 0

3 years ago

8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.

loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

$^8C_4\times ^9C_5\times^9C_2\times^7C_3$

$=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200$