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LUCKY_DIMON [66]
4 years ago
5

What does the phrase rise over run refer to when defining slope

Physics
1 answer:
horsena [70]4 years ago
4 0
I just learned this. Rise over run is also rise divided by run.  The rise refers to the y axis (since y is vertical so it's rising), and run refers to the x axis (Since x is horizontal so it's running straight).  So in other words, rise/run = y/x.  To calculate the slope, you do y/x.  For example, if you have y=3 and x=8, then your slope is 3/8.  To plot that on a graph, you start from your point, and go up three, and across 8.  Hope this helps.
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Check all of the following statements that describe velocity.
Nata [24]

Answer:

Choices A, B, and C are correct.

Explanation:

Let us look at each of the choices one by one:

A. It is a vector

Yes. Velocity is a vector, or it's a speed with direction.

B. It is the change in displacement divided by the change in time.

Yes. The velocity can be written as

v = \dfrac{\Delta\bold{x}}{\Delta t}

where \bold{x} is the displacement—a vector quantity.

C. It can be measured in meters per second.

Yes. The units of velocity are m/s, but also with a unit vector indicating the direction.

D. It is the slope of the acceleration vs. time graph.

Nope. The velocity is the slope of displacement vs. time graph.

Hence, only choices A, B, and C are correct.

4 0
3 years ago
Classify the following matter
AURORKA [14]

Answer:

Woah

Explanation:

7 0
3 years ago
How much heat is needed to melt 16.5kg of silver that is initially at 20*c?
zubka84 [21]
The Specific Heat Capacity of silver is 230 J/kgK, melting point is 961.8 C so the difference is 941.8K. Now we simply do q=230J/kgK*16.5kg*941.8K and that is 3 574 131 J
8 0
4 years ago
A train moves from rest to a speed of 30 m/s in 32.0 seconds. What is its acceleration?​
kramer

Answer:

0.94m/s (squared)

Explanation:

a=change in velocity/time

a=v-u/t

a=32-0=32/32

a=0.94m/s (squared)

6 0
3 years ago
One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicula
qwelly [4]

Answer:

Bnet=1.006*10^-6T

Explanation:

One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 5.9 m, 0), and carries a current of 41 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 1.7 m, 0)?

the magnetic field Bnet=\sqrt{b1^2+b2^2}

the magnetic field due this long wire is given by

B1=∨I1/(2\pi *R1)..............................1

B2=∨I2/(2\pi *R2)............................2

Bnet=\sqrt{(vI1/2*pi*R1)^2+(vI2/2*pi*R2)^2}.......................3

Bnet=v/2*pi\sqrt{(I1/R1)^2+(i2/R2)^2}

Bnet=4*pi*10^-7/(2\pi)\sqrt{(43/1.7)^2+(41/29.5)^2}

Bnet=0.0000002*(641.72)^.5

Bnet=1.006*10^-6T

8 0
4 years ago
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