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3 years ago

What does the phrase rise over run refer to when defining slope

1 answer:

4 0

I just learned this. Rise over run is also rise divided by run. The rise refers to the y axis (since y is vertical so it's rising), and run refers to the x axis (Since x is horizontal so it's running straight). So in other words, rise/run = y/x. To calculate the slope, you do y/x. For example, if you have y=3 and x=8, then your slope is 3/8. To plot that on a graph, you start from your point, and go up three, and across 8. Hope this helps.

You might be interested in

Find the angle formed by two forces of 7N and 15N respectively if its result is worth 20N

nadezda [96]

First, you need to make certain assumptions before solving this question. Why? Because there are no information given about the direction of these forces. In such questions as above, ALWAYS make the following assumptions:

1) Take first force, say $F_{1}$ , and assume that it is pointing towards the x-direction.

Let us take the 7N force! By keeping the above assumption in our minds, the force vector would be like:
$F_{1}$ = $7i$ , where $i$ = Unit vector in the x-direction.

2) Take the second force, say $F_{2}$ , and assume that it is making an angle $\alpha$ with the first force $F_{1}$ .

Let us take the 15N force! By keeping the above assumption in our minds, the forces vector would be like:

$F_{2} = (15*cos \alpha)i + (15*sin \alpha )j$

Now from simple vector addition, we know that,
$F_{R} = F_{1} + F_{2}$ --- (A)

Where $F_{R}$ = Resultant vector.
NOTE: In equation (A), all forces are in vector notation. Assume that there is an arrow head on top of them.

Let us find $F_{1}+F_{2}$ first!
$F_{1}+F_{2}$ =   $7i+(15*cos \alpha)i + (15*sin \alpha )j$

=> $F_{1}+F_{2}$ =   $(7+15*cos \alpha)i + (15*sin \alpha )j$

Now the magnitude of $F_{1}+F_{2}$ is,
| $F_{1}+F_{2}$ | = $\sqrt{ (7+ 15*cos \alpha)^{2} + (15*sin \alpha )^{2}}$

=> | $F_{1}+F_{2}$ | = $\sqrt{ 49 + 225*(cos \alpha)^{2} + 210*(cos \alpha)+ 255*(sin \alpha )^{2}}$

Since $(sin \alpha)^{2} + (cos \alpha)^{2} = 1$ , therefore,

=> | $F_{1}+F_{2}$ | = $\sqrt{ 49 + 225 + 210*(cos \alpha)}$

Since  | $F_{1}+F_{2}$ | = | $F_{R}$ |, and the magnitude of the resultant force is 20N, therefore,

| $F_{R}$ | = | $F_{1}+F_{2}$ |
20 = $\sqrt{ 49 + 225 + 210*(cos \alpha)}$

Take square on both sides,
400 = $49 + 225 + 210*(cos \alpha)$
$(cos \alpha) = \frac{3}{5}$

$\alpha = 53.13^{o}$

Ans: Angle formed by the two forces, 7N and 15N, is: 53.13°

-israr

4 0

3 years ago

I need help... anyone know this?

julsineya [31]

Answer:mp

Explanation:

7 0

3 years ago

An actor has a mass of 70 kg. Gravitational field strength = 9.8 N/kg. Use the following equation to calculate the weight of the

GalinKa [24]

This is a way of measuring how much gravity there is. The formula is: weight/mass = gravitational field strength.

Gravitational field strength = Weight/mass unit is N/kg

Weight = mass x gravitational field strength unit is N

On Earth the gravitational field strength is 10 N/kg. Other planets have different gravitational field strengths. The Moon has a gravitational field strength of 1.6 N/kg. You might have seen films of astronauts leaping high on the moon.

Here on Earth, if I jump I am pulled back to ground by gravity. What is my weight? My mass is 80kg and if we multiply by gravitational field strength (10N/kg) - my weight is 800N. Now if I go to the moon, my mass will be the same, 80kg. We multiply that by the moon's gravitational field strength, which is 1.6 N/ kg. That means my weight on the moon is 128N. So I have different weights on the Earth and on the Moon. That's why astronauts can jump high into the air on the moon - they're lighter up there.

Jupiter is a very large planet with strong gravitational field strength of 25 N/ kg. My body is 80kg. If I go to Jupiter my weight is going to be 25 x 80 = 2,000 N. That means I wouldn't be able to get off the ground or stand up straight! I would probably be lying down all the time there. So weight varies depending on which planet you are on. You can find out more yourself by looking up tables of weight on different planets.

8 0

2 years ago

When an object stops moving, changes speed, or changes direction, how does a scientists describe that condition?

soldi70 [24.7K]

The answer is A. unbalanced forces

5 0

3 years ago

Calculate the rate of some reaction that obeys Avrami kinetics, assuming that the constants n and k have values of 2.0 and 0.006

Aliun [14]

Answer:

rate=0.093 s⁻¹

Explanation:

Given Data

n=2.0

k=0.006

assume y=0.5 because it is not given in question

rate=?

Solution

As we know that

$e^{-kt^{n} } =1-y\\t^{n}=-\frac{ln(1-y)}{k}\\ t=-(\frac{ln(1-y)}{k} )^{\frac{1}{n} }\\ t=-(\frac{ln(1-0.5)}{0.006} )^{\frac{1}{2} }\\t=10.74 seconds\\rate=\frac{1}{t}\\ rate=\frac{1}{10.74} \\rate=0.093s^{-1}$

8 0

3 years ago