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Usimov [2.4K]
3 years ago
6

To make the next delivery, Sam-I-Am goes 45 mi/h for 2 hours. How far did he travel in that time?

Physics
1 answer:
andrezito [222]3 years ago
5 0

Hello =D

This problem is about cinematic

So

V = 45 mi/h

t = 2 h

Then

V= X/t

X = V*t

Then

X = (45)*(2)

X = 90 mi

Best regards

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Answer:

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Explanation:

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(a). The frictional force is given by

F_{fri} = \mu R_{N}

R_{N} = mg \cos \theta

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Therefore the frictional force

F_{fri} = 0.22 × 29.3

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F_{net} = 30 - 6.446

F_{net} = 23.554 N

The net force acting on the block is given by

F_{net}  = ma

23.554 = 3.9 × a

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2 years ago
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Answer:

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pochemuha

Answer:

the horizontal distance covered by the cannonball before it hits the ground is 327.5 m

Explanation:

Given;

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initial vertical velocity of the cannonball, Uy = 0

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The horizontal distance covered by the cannonball before it hits the ground is calculated as;

X = U_x \times \ t\\\\X = 50 \times \ 6.55\\\\X = 327.5 \ m

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