1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cestrela7 [59]
4 years ago
7

E4.Suppose Galileo’s pulse rate was 75 beats per minute. How many beats per second is this? What is the time in seconds between

consecutive pulse beats? How far (in meters) does an object fall in this time when dropped from rest? What is this distance in feet (use the conversion factors on the inside front cover)?
Physics
1 answer:
Umnica [9.8K]4 years ago
3 0

Answer

given,

Galileo's pulse rate = 75 beats per minutes

Beats per second

1 minutes = 60 s

pulse rate = \dfrac{75}{60}

                  = 1.25 beats/s

times in second

t = \dfrac{1}{1.25}

      t = 0.8 s/pulse

distance of the object

initial velocity = 0 m/s

s = ut + \dfrac{1}{2}gt^2

s = \dfrac{1}{2}\times 9.8\times 0.8^2

      s = 3.14 m

distance in feet

  1 m = 3.28 ft

 3.14 m = 3.14 x 3.28 ft

             = 10.3 ft

distance in feet is equal to 10.3 ft.

You might be interested in
What is the correct answer?
pentagon [3]

Answer:

B) x^2+6x+8

Explanation:

x-4 | x^3+2x^2-16x-32

    -  x^3-4x^2             <-- (x-4)(x^2)

_________________

              6x^2-16x-32

           -  6x^2-24x     <-- (x-4)(6x)

_________________

                          8x-32

                       -  8x-32 <- (x-4)(8)

___________________________

                                 0 | x^2+6x+8

This means the answer is B) x^2+6x+8

             

3 0
3 years ago
An astronaut lands on a new, recently discovered planet in a different star system. The astronaut measures the acceleration due
Nezavi [6.7K]

Answer:

The radius of the new planet is ~2.04 * 10⁶ m, or 2,041,752 m.

Explanation:

We can use Newton's Law of Universal Gravitation:

  • \displaystyle F_g=G\frac{Mm}{r^2}

Let's look at Newton's 2nd Law:

  • F=ma

We can set these equations equal to each other:

  • \displaystyle G\frac{Mm}{r^2} =ma

The mass of the second mass (astronaut) cancels out. We are left with:

  • \displaystyle G\frac{M}{r^2} =a

We are solving for the radius of the new planet, so we can rearrange the equation:

  • \displaystyle r=\sqrt{\frac{GM}{a} }

Substitute in our known values given in the problem (<u><em>G = 6.67 * 10⁻¹¹ </em></u><em> ; </em><u><em>M = 7.5 * 10²³</em></u><em> ; </em><u><em>a = 12</em></u>).

  • \displaystyle r =\sqrt{\frac{(6.67\times 10^{-11})(7.5 \times 10^{23}}{12} }
  • r=2.04 \times 10^6

The radius of the new planet is ~2.04 * 10⁶ m.

3 0
3 years ago
I am boring and you can talk to me?
sladkih [1.3K]
SURE HI



HI HOW R U


Hello
4 0
3 years ago
Read 2 more answers
The Hubble Space Telescope in orbit above the Earth has a 2.4 m circular aperture. The telescope has equipment for detecting ult
strojnjashka [21]

Answer:

Option d

The minimum angular separation between two objects that the Hubble Space Telescope can resolve is 4.8x10^{-8}rad.  

Explanation:

The resulting image in a telescope that will be gotten from an object is a diffraction pattern instead of a perfect point (point spread function (PSF)).

That diffraction pattern is gotten because the light encounters different obstacles on its path inside the telescope (interacts with the walls and edges of the instrument).

 

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.    

 

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction pattern maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in analytical way by means of the Rayleigh criterion.          

\theta = 1.22\frac{\lambda}{D}  (1)

Where \lambda is the wavelength and D is the diameter of the telescope.

Notice that it is necessary to express the wavelength in the same units than the diameter.

\lambda = 95nm \cdot \frac{1x10^{-9}m}{1nm} ⇒ 9.5x10^{-8}m

Finally, equation 1 can be used.

\theta = 1.22(\frac{9.5x10^{-8}m}{2.4m})

\theta = 4.8x10^{-8}rad              

Hence, the minimum angular separation between two objects that the Hubble Space Telescope can resolve is 4.8x10^{-8}rad.    

5 0
4 years ago
A substance that contains only one kind of matter is known as a(n)
Anna35 [415]
An element would be the type of substance that only contains one kind of matter.
3 0
4 years ago
Other questions:
  • Pls answer these questions I beg u!! And use the diagram for answering the questions pls help!! I will make u the BRAINLIEST!!!
    6·1 answer
  • The idea that our bodies help our minds think is called:
    13·2 answers
  • Wladimir Köppen’s climate system was developed _____.
    10·1 answer
  • A photon with a frequency of 5.48 × 10^14 hertz is emitted when an electron in a
    5·1 answer
  • 5. What is the density of 4.5 mL of a liquid that has a mass of 1.3 grams?
    11·2 answers
  • When an element undergoes nuclear transmutation, the result is a completely different
    8·2 answers
  • The moon is made up mostly of _______, similar to minerals on earth
    9·1 answer
  • Peregrine falcons are the fastest birds in the world, reaching max- imum speeds of up to 320 km/h (88 m/s) during a hunting stoo
    12·1 answer
  • A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
    11·1 answer
  • Which of the following is the main difference between speed and velosity? A) speed is measured over time B) velocity has both sp
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!