Answer:
magnitude of the frictional torque is 0.11 Nm
Explanation:
Moment of inertia I = 0.33 kg⋅m2
Initial angular velocity w° = 0.69 rev/s = 2 x 3.142 x 0.69 = 4.34 rad/s
Final angular velocity w = 0 (since it stops)
Time t = 13 secs
Using w = w° + §t
Where § is angular acceleration
O = 4.34 + 13§
§ = -4.34/13 = -0.33 rad/s2
The negative sign implies it's a negative acceleration.
Frictional torque that brought it to rest must be equal to the original torque.
Torqu = I x §
T = 0.33 x 0.33 = 0.11 Nm
Answer:
he covered 80km his displacement was 20km
Explanation:
displacement is the distance from the starting point so in this case its 20 (50-30) and total distance covered is how many kilometers he drove in total
I think Is b the first question
Answer:
Force=29789.55 N
Explanation:
Given data
dimension=3.5m by 2.1m
P(outside pressure)=0.96 atm
P(inside pressure)=1.00 atm
Force=?
Solution
Area=L×W
A=(3.5)×(2.1)
As we know
F=PA
For P(pressure)
P=P(inside)-P(outside)
P=1.00-0.96
P=0.04 atm
convert atm to pascal (pa) we get
P=4053 pa
F=PA
F=(4053)×(7.35)
F=29789.55 N
