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Lubov Fominskaja [6]
3 years ago
5

A planet has two moons. The first moon has an orbital period of 1.262 Earth days and an orbital radius of 2.346 x 104 km. The se

cond moon has an orbital radius of 9.378 x 103 km. What is the orbital period of the second moon?
Physics
1 answer:
Maslowich3 years ago
4 0
Kepler's third law hypothesizes that for all the small bodies in orbit around the same central body, the ratio of (orbital period squared) / (orbital radius cubed) is the same number. 

Moon #1:  (1.262 days)² / (2.346 x 10^4 km)³

Moon #2:  (orbital period)² / (9.378 x 10^3 km)³

Equating the ratio:
(1.262 days)² / (2.346 x 10^4 km)³  = (orbital period)² / (9.378 x 10^3 km)³

Cross-multiply:
(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³

Divide each side by (2.346 x 10^4)³:

(Orbital period)² = [ (1.262 days)² x (9.378 x 10^3)³ ] / (2.346 x 10^4)³

               =  0.1017 day²

Orbital period = 0.319 Earth day = about 7.6 hours.
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solid at room temperature

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Mathematically, Charles law is given by the formula;

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3 years ago
A 10 cm diameter pulley is used to lift a bucket of cement weighing 400 N. How much force must be applied to the rope to lift th
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hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა

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\large \bold {ANSWER}

Considering that the pulley is fixed, the force applied should be equal to the weight of the object - of 400N.

\large \bold {EXPLANATION}

Pulleys or pulleys are mechanical tools used to assist in the movement of objects and bodies. There are two types of pulleys: fixed and movable. While the fixed pulley changes the direction of force, the moving pulley helps to decrease the force needed to move the object or body in question.

As the statement only tells us a pulley, we must consider that it is fixed, <u>because generally when it is mobile, this information is highlighted in the question</u>.

In this way, a fixed pulley only changes the direction of the applied force. Thus, the force must have the same magnitude as the weight of the object to be moved. If the bucket weighs 400N, the force applied to the pulley must be 400N.

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2 years ago
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The periodic table is in increasing atomic mass. Hope this helped.
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the total positive charge is QQQ = 1.62×10−6 CC , what is the magnitude of the electric field caused by this charge at point P,
balu736 [363]

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6.1 × 10^9 Nm-1

Explanation:

The electric field is given by

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d = distance of separation = 1.53 mm = 1.55 × 10^-3 m

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E= 6.1 × 10^9 Nm-1

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