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Umnica [9.8K]
3 years ago
5

This is the problem that needs to be graphed 4y=-8x+12

Mathematics
1 answer:
love history [14]3 years ago
3 0

Answer:

graph as illustrated

Step-by-step explanation:

4y = - 8x + 12    ..... both side divided by 4 to simplify the equation

y = -2x + 3

find two points on the line

x = 0, y = 3    .... (0,3)

x = 1, y = 1      ..... (1,1)

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For which inequality is {x | x R, x > 6} the solution set?
CaHeK987 [17]

Answer:

C

Step-by-step explanation:

<em>B: 2X + 12 > 3</em>

2x > -9

x> -9/2

<em>C: 2X - 5 > 7</em>

2x > 12

x > 6

<em>D: 2x - 6 > 24</em>

2x > 30

x > 15

Hope this helps ^-^

6 0
2 years ago
Cu cît este mai mic împatritul lui63 fata de înnoitul rasturnatului sau?
never [62]
Indeed you need to speech English
4 0
3 years ago
the formula used to find the area of a triangle is A= 1/2bh, where is A of the triangle, b is the length of the base of the tria
aliya0001 [1]
If you are doing a literal equation all you have to do is isolate the h.
First get rid of the fraction by multiplying both sides by 2.
2a=bh
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Hope this helps!
7 0
3 years ago
Read 2 more answers
Helppppppppppppppppppp please
Svetlanka [38]

Answer:

\sqrt[]{\frac{x+8}{4}}-3

Step-by-step explanation:

g(x)=4(x+3)^2-8

First rewrite g(x) as y

y=4(x+3)^2-8

Now swap y and x

x=4(y+3)^2-8

Add 8 on both sides.

x+8=4(y+3)^2-8+8

x+8=4(y+3)^2

Divide by 4.

\frac{x+8}{4} =\frac{4(y+3)^2}{4}

\frac{x+8}{4}=(y+3)^2

Extract the square root on both sides.

\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}

\sqrt[]{\frac{x+8}{4}}=y+3

Subtract 3 on both sides.

\sqrt[]{\frac{x+8}{4}}-3=y+3-3

\sqrt[]{\frac{x+8}{4}}-3=y

4 0
2 years ago
Krisa divides a number by 10. Then she divides the same number by 50. Which quotient is greater? How can you tell?
weeeeeb [17]

Step-by-step explanation:

the quotient of 10 is bigger than the quotient of 50

6 0
3 years ago
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