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ivanzaharov [21]
3 years ago
7

Five chips numbered 1 through 5 are placed in a bag. A chip is drawn and replaced. Then a second chip is drawn. Find the probabi

lity that one chip is even AND the other is odd. (Hint: You can choose an even chip and then an odd chip, or an odd chip and then an even chip.)
Mathematics
2 answers:
Xelga [282]3 years ago
4 0
1 out of 5, since ther are still 5 chips in the bag
hope thishelps
;-)
andrezito [222]3 years ago
4 0

There are 3 odd and 2 even numbers involved here.

So Prob( even then odd) = 2/5 * 3/5 = 6/25

Pro(odd then even) = 3/5 * 2/5 = 6/25

Therefore  Prob( either of the above) = 6/25 + 6/25 = 12/25 (answer)

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Arlecino [84]

Answer:

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Step-by-step explanation:

Given expression:

    (x + 3)²  = -16

 

Problem;

   Solve for x;

Solution:

 To solve for x; we use the factorization method;

     Take -16 to the left of the equation;

      (x + 3)²  = -16

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if    x² + y²  = (x + y)(x - y)

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       x + 7  = 0 or x - 1 = 0

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6 0
2 years ago
Reposting this because no body gave me the equation. An equation would be appreciated :)
o-na [289]

bring the like terms together,

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