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3 years ago

11

If a test has 30 questions on it and a student answers 18 of the questions correctly, then what percentage would the student get

on the test?

1 answer:

german3 years ago

4 0

The would get a 60%. To find this you need to divide 18/30.

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Kaylis [27]

Answer:

90 degrees

Step-by-step explanation:

Step 1: State what is known

Notice that the 2 lines cut the square in half and create 4 congruant triangles. We know a full circle is 360 degrees and the intersection is a perfect circle formed by 4 angles. We can find the angle AEB by dividing 360 by 4 which gives you 90 degrees

8 0

2 years ago

Bill likes the outdoors, nature walking, and hunting deer and turkeys.

Lelechka [254]

Answer:

teacher got the answer physical theripists wrong on usatestprep

the naswer is teacher i promise it is teacher

Step-by-step explanation:

5 0

3 years ago

What is the volume of the square-based pyramid?

grandymaker [24]

Answer:

Volume of square-based pyramid = 96 in³

Step-by-step explanation:

Given:

Base side of square = 6 inch

Height of pyramid = 8 inch

Find:

Volume of square-based pyramid

Computation:

Area of square base = Side x Side

Area of square base = 6 x 6

Area of square base = 36 in²

Volume of square-based pyramid = (1/3)(A)(h)

Volume of square-based pyramid = (1/3)(36)(8)

Volume of square-based pyramid = (1/3)(36)(8)

Volume of square-based pyramid = (12)(8)

Volume of square-based pyramid = 96 in³

6 0

3 years ago

Help which graph describes exponential decay

DIA [1.3K]

Answer:

Graph 2.

Step-by-step explanation:

The graph is decreasing.

Hope this helps!

If not, I am sorry.

6 0

2 years ago

Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

6 0

3 years ago