Answer:
x² + 18x +81
x² - 14x +49
4x²- 4x - 1
Step-by-step explanation:
multiply the x in the first parentheses by x and 9 in the other parentheses and
multiply the 9 in the first parentheses by x and 9 in the other parentheses and add all together
(x+9)(x+9)
x² + 9x + 9x + 81
x² + 18x +81
multiply the x in the first parentheses by x and -7 in the other parentheses and multiply the -7 in the first parentheses by x and -7 in the other parentheses and add all together
(x-7)(x-7)
x² -7x - 7x +49
x² - 14x +49
(2x-1)² is the same as (2x-1)(2x-1)
multiply the 2x in the first parentheses by 2x and -1 in the other parentheses and multiply the -1 in the first parentheses by 2x and -1 in the other parentheses and add all together
(2x-1)(2x-1)
4x²-2x-2x+1
4x²- 4x - 1
Answer:
- Angle 'a' is an alternating exterior angle with one angle in the triangle and therefore congruent to one angle in the triangle formed by lines m, x, and y.
- Angles 'b' and 'c' are vertical angles with the other two angles in the triangle and therefore congruent to two other angles in the triangle
Step-by-step explanation:
Vertical angles are angles that are equal to each other but in opposite direction. The angles b and c have vertical angles on the triangle Q while alternate exterior angles are equal angles that lie on different lanes cutting through an axis.
Angles on a plane can be congruent if they are vertical equals or alternating exterior angles.
The function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.
For determining the end behavior of a polynomial, there is just 2 things to take notice of.
1. Is the leading coefficient positive or negative?
2. Is the degree of the polynomial odd or even?
For odd ordered polynomials, the curve starts in either quadrant II or III, and ends in quadrant IV, or I. Basically, if it's positive, the curve enters the graph somewhere in the lower left hand region, and exits the graph in the upper right hand region. If the coefficient is negative, it enters in the upper left hand region, and exits in the lower right hand region.
For even ordered polynomials, the graph is either concave upwards (positive leading coefficient) or concave downwards (negative leading coefficient).
In this problem, 14 is an even number and since the coefficient is positive, the function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.
