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Sholpan [36]
3 years ago
13

A group of adults and students went on a class trip to Washington, DC. The number of male students was 1 more than 7 times the n

umber of adults. The number of female students was half the number of male students. If the total number of people who went on the trip is 82, find the numbers of male students and female students. The number of male students is . The number of female students is . NextReset
Mathematics
1 answer:
algol [13]3 years ago
4 0
Alright.
So let's say the number of adults is x.
Therefore, the number of boys is 7x + 1.
And then the total amount of girls is 3.5x + 0.5
So then:
x + 7x + 1 + 3.5x + 0.5 = 82
11.5x + 1.5 = 82
11.5x = 80.5
x = 7
So now we can figure out the number of male and female students.
Male students = 7x + 1
7*7 + 1
49 + 1
50
Male Students = 50
Female students = half of 50
50/2 = 25
Female Students = 25
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A jar contains many coins. The probability that a coin randomly selected from the jar is a penny is 10%. A week later, the proba
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B) Two coins are tossed, find the probability that one head only is obtained.
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earnstyle [38]

Answer:

Step-by-step explanation:

y-2=3(x-5)

y-2=3x-15

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y-12= -2(x-3)

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A development economist is studying income growth in a rural area of a developing country. The last census of the population of
kykrilka [37]

Answer:

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.  

Step-by-step explanation:

Data given and notation  

\bar X=433.75 represent the mean height for the sample  

\sigma=\sqrt{2500}=50 represent the population standard deviation for the sample  

n=100 sample size  

\mu_o =425 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean height actually is higher than the mean height for men in 1960, the system of hypothesis would be:  

Null hypothesis:\mu \leq 425  

Alternative hypothesis:\mu > 425  

Since we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{433.75-425}{\frac{50}{\sqrt{100}}}=1.75    

P-value

Since is a one right tail test the p value would be:  

p_v =P(z>1.75)=1-P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.  

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3 years ago
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