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Doss [256]
3 years ago
15

Find dy/dx if f(x) = (x + 2)^7x.

Mathematics
1 answer:
lana [24]3 years ago
4 0
\dfrac{\mathrm d}{\mathrm dx}(x+2)^{7x}=\dfrac{\mathrm d}{\mathrm dx}e^{7x\ln(x+2)}

By the chain rule, the derivative reduces to

e^{7x\ln(x+2)}\dfrac{\mathrm d}{\mathrm dx}(7x\ln(x+2))=(x+2)^{7x}\dfrac{\mathrm d}{\mathrm dx}(7x\ln(x+2))

Then using the product rule, we get

(x+2)^{7x}\left(7\ln(x+2)+\dfrac{7x}{x+2}\right)
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Nikki gathered data about the length of time she spent listening to the radio and the number of commercials she heard. She organ
svet-max [94.6K]

Answer:

Option C

63

Step-by-step explanation:

Using the given equation y = 0.338x − 1.387 and since you're given the the number of commercials, you substitute this for y hence

20= 0.338x − 1.3877

20+1.3877=0.338x

0.338x=21.3877

x=21.3877/0.338=63.27514793

Rounding off, x=63. \the question says x represents the minutes spent hence the answer is 63

8 0
3 years ago
If p is true and q is false, then p ∧ ~q is true.
Nadusha1986 [10]

Answer:

  True

Step-by-step explanation:

  true ∧ (not false) . . . . . . . has a truth value of <em>True</em>

_____

The "and" operator gives <em>true</em> if all of its operands are <em>true</em>.

5 0
3 years ago
Is(-3,7) a solution of the equation y=x+15?​
Rudiy27

Answer:

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7 0
3 years ago
14 x 1 = 14 exemplifies which property
NNADVOKAT [17]
Uhhhhh Multiplication
7 0
2 years ago
Read 2 more answers
At 3 p.m. an oil tanker traveling west in the ocean at 14 kilometers per hour passes the same spot as a luxury liner that arrive
schepotkina [342]
<span>N(t) = 16t ; Distance north of spot at time t for the liner. W(t) = 14(t-1); Distance west of spot at time t for the tanker. d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t. Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is N(t) = 16t Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is W(t) = 14(t-1) The distance between the 2 ships is easy. Just use the pythagorean theorem. So d(t) = sqrt(N(t)^2 + W(t)^2) If you want the function for d() to be expanded, just substitute the other functions, so d(t) = sqrt((16t)^2 + (14(t-1))^2) d(t) = sqrt(256t^2 + (14t-14)^2) d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) ) d(t) = sqrt(452t^2 - 392t + 196)</span>
3 0
3 years ago
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