Answer:
Option C
63
Step-by-step explanation:
Using the given equation y = 0.338x − 1.387 and since you're given the the number of commercials, you substitute this for y hence
20= 0.338x − 1.3877
20+1.3877=0.338x
0.338x=21.3877
x=21.3877/0.338=63.27514793
Rounding off, x=63. \the question says x represents the minutes spent hence the answer is 63
Answer:
True
Step-by-step explanation:
true ∧ (not false) . . . . . . . has a truth value of <em>True</em>
_____
The "and" operator gives <em>true</em> if all of its operands are <em>true</em>.
Answer:
I believe it is not. that would mean 7=-3+15 and therefore 7=12, which is not a true statement.
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>