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maria [59]
4 years ago
5

What is required for the processing of food from raw materials?

Business
1 answer:
nevsk [136]4 years ago
7 0
Factories are required 
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Great Lakes Packing has two bond issues outstanding. The first issue has a coupon rate of 3.54 percent, a par value of $1,000 pe
grandymaker [24]

Answer:

3.20%

Explanation:

The firm's weighted average aftertax cost of debt can be determined by first of all determining the before-tax cost of each debt.

Using a financial calculator, the before-tax costs of debt are ascertained as follows:

Bond 1:

N=8(number of semiannual coupons in 4 years)

PMT=17.70  (semiannual coupon=face value*coupon rate/2=$1,000*3.54%/2=$17.70)

PV=-1030(current price=$1000*103%=$1030)

FV=1000(the face value is $1000)

CPT

I/Y=1.37%(the semannual yield, annual yield=1.37%*2=2.74%)

after-tax cost of first debt=2.74%*(1-39%)=1.67%

Bond 2:

N=46(number of semiannual coupons in 23  years)

PMT=30.50 (semiannual coupon=face value*coupon rate/2=$1,000*6.10%/2=$30.50)

PV=-950(current price=$1000*95%=$950)

FV=1000(the face value is $1000)

CPT

I/Y=3.26%%(the semannual yield, annual yield=3.26%%*2=6.52%)

after-tax cost of second debt=6.52%*(1-39%)=3.98%

market value of first debt=$3.8 million*103%=$3,914,000

market value of second debt=$8.1 million*95%=$7,695,000

total market value of debts=$3,914,000+$7,695,000=$11,609,000

firm's weighted average aftertax cost of debt=(1.67%*$3,914,000/$11,609,000)+(3.98%*$7,695,000/$11,609,000)

firm's weighted average aftertax cost of debt=3.20%

5 0
3 years ago
_______ is a third-party certification seal program that verifies that a business protects confidential information with SSL enc
FrozenT [24]

An SSL Certificate is a third-party certification seal program that verifies that a business protects confidential information with SSL encryption. SSL stands for secure sockets layer and this helps identifiy the third party by keeping sensitive information protected.

6 0
3 years ago
Winter's Toyland has a debt-equity ratio of .57. The pretax cost of debt is 8.2 percent and the required return on assets is 14.
True [87]

Answer:

<em>WACC 10.995</em>

Explanation:

We solve using the Weighted average cost of capital assuming a tax rate of 0% as we have to ignore taxes. Hence, we get:

WACC = K_e(\frac{E}{E+D}) + K_d(1-t)(\frac{D}{E+D})

Ke 0.14700

Equity weight 0.43

Kd 0.082

Debt Weight 0.57

t 0

WACC = 0.147(0.43) + 0.082(1-0)(0.57)

WACC 10.99500%

6 0
3 years ago
Read 2 more answers
What is the introduction of management ?​
Anarel [89]

Answer:

This view opens the opportunity to manage oneself, a pre-requisite to attempting to manage others. Management functions include: Planning, organizing, staffing, leading or directing, and controlling an organization (a group of one or more people or entities) or effort for the purpose of accomplishing a goal.

Explanation:

3 0
3 years ago
Credit card debt. The average credit card debt for college seniors in $3262. If the debt is normally distributed with a standard
Reika [66]

Answer:

  • 0.98 approximately
  • 0.25 approximately
  • 0.34 approximately

Explanation:

standard deviation by which debt is distributed  = $1100

average credit card debt for college seniors = $3262

A)  probability that senior owes at least $1000

P (x ≥ 1000 ) = P ( Z ≥ \frac{1000- \alpha }{\beta }  )

where \alpha = average credit card debt = $3262

\beta = standard deviation = $1100

Z = random variable representing credit card debt for college seniors

back to equation P ( Z ≥ \frac{1000- 3262}{1100} )

therefore  P ( z ≥ -2.06 )

                 1 - p ( z ≤ -2.06 )

therefore probability of the senior owing $1000 = 1 - 0.0199 = 0.9801

B) probability that senior owes more than $4000

p ( x ≥ 4000) = P ( Z ≥ \frac{4000 - \alpha }{\beta } )

                     = P ( Z ≥ \frac{4000 - 3262}{1100} )

                     = 1 - p ( Z ≤ 0.67 ) therefore probability that senior owes more than $4000 = 1 - 0.7468 = 0.2514

C ) Probability that the senior owes between $300 and $4000

P ( 3000 ≤ x ≤ 4000) = P ( \frac{3000 - \alpha }{\beta } ≤ Z ≤ \frac{4000 - \alpha }{\beta } )

                                  = P ( \frac{3000 - 3262}{1100} ≤ z ≤ \frac{4000 - 3262}{1100} )

                                  = P ( - 0.24 ≤ z ≤ 0.67 )  

                                 = p ( z ≤ 0.67 ) - p ( z ≤ - 0.24 )        

                                 = 1 - p ( z ≥ 0.67 ) - 1 - p ( z ≥ -0.24 )

                                 = 0.7846 - 0.4052 = 0.3434                  

5 0
3 years ago
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