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miss Akunina [59]
4 years ago
5

An oil refinery is located 1 km north of the north bank of a straight river that is 2 km wide. A pipeline is to be constructed f

rom the refinery to storage tanks located on the south bank of the river 5 km east of the refinery. The cost of laying pipe is $300,000/km over land to a point P on the north bank and $600,000/km under the river to the tanks. To minimize the cost of the pipeline, how far downriver from the refinery should the point P be located? (Round your answer to two decimal places.)
Business
1 answer:
Kaylis [27]4 years ago
8 0

Answer:

The point p should be located to 4.42 km far from the refinery

Explanation:

Minimum of these costs occurs when <em>x = 1/\sqrt{3}</em> , so <em>distance </em>should be <em>m</em> km to the east of the refinery.

<em>m = 5 - x </em>

<em>m = 5 - 1/\sqrt{3}</em>

<em />

m = 4.42 km

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3 years ago
Read 2 more answers
In 2011, the imaginary nation of Maconia had a population of 8,200 and real GDP of 210,500.
vazorg [7]

Answer:

C. 226,416

Explanation:

Firstly, we find the GDP per person for 2011.

Next, we calculate the 5% GDP per person increase in 2012

Finally, we calculate for GDP in 2012 using available data gotten

So,

Given that

In 2011,

Real GDP = 210,500

Population = 8200

GDP per person for 2011 = 210,500 ÷ 8200

= 25.67 approximately.

In 2012, there was a 5% growth in GDP per person, therefore,

GDP person 5% increase in 2012 = (5÷100) × 25.6707317073

= 0.05 × 25.6707317073

= 1.2835365854

2012 GDP per person = 25.6707317073 + 1.2835

= 26.9542682927

Or

5% increase of 25.6707317073 = 25.6707317073 × 1.05 = 26.9542682927

So, to get the GDP in 2012,

GDP = GDP per person × population

Where GDP per person = 26.9542682927

Population = 8400

Thus,

Real GDP = 26.9542682927 × 8400

= 226,415.8

Approximately = 226,416 to the nearest dollar.

6 0
3 years ago
An energy efficiency project has a first cost of $400,000, a life of 10 years, and no salvage value. Assume that the interest ra
Leokris [45]

Answer:

a) What is the expected annual savings and the expected PW?

Expected annual savings = ($80,000 x 20%) + ($50,000 x 55%) + ($40,000 x 25%) = $53,500

b) Compute the PW for the pessimistic, most likely, and optimistic estimates of the annual savings. What is the expected PW?

PW of expected annual savings = ($53,500 x 6.145) - $400,000 = $328,757.50 - $400,000 = $71,242.50

c) Do the answers for the expected PW match? Why or why not?

Expected PW = ($91,600 x 20%) + (-$92,750 x 55%) + (-$154,200 x 25%) = -$71,242.50

Yes, they match.

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3 years ago
In 2021, Ryan Management collected rent revenue for 2022 tenant occupancy. For financlal reporting, the rent Is recorded as defe
fenix001 [56]

Answer and Explanation:

The Journal entry is shown below:-

1. Income Tax Expense Dr, $336 million  

Deferred Tax Assets Dr, $29 million

($116 million  × 25%)

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($1,460 × 25%)

(Being income tax and deferred tax is recorded)

2. Income Tax Expense Dr, $400 million

          To Income Tax Payable  $340  million

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6 0
3 years ago
Sort the examples below into the appropriate bin. Think about which factors could lead to more toxic substances being released i
Zielflug [23.3K]

Answer:

1. Causes: commercial production of many chemicals massive use of chemicals in food, agriculture, medicine, and industry

2. Consequences: increase in reproductive disorders contamination of soil, air, and water bioaccumulation and biomagnification of toxins in the food chain.

3. Solutions: consumer choice of low-toxicity products stricter regulations requiring that consumer products be thoroughly tested before being released to market.

Explanation:

This factors could lead to more toxic substances being released into the environment (causes), the consequences that result from toxic substances in the environment, and possible solutions to save environmental degradation.

8 0
3 years ago
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