Answer:
200+64=264
Step-by-step explanation
You mulitply the 2 figures i.e 8x5x5 and 8x8x1 to find the volume of each shape then simply add and you get 264.
Graph the linear equation. 3x-4y= 24
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Let x = 0, then y = -6
Let y = 0, then x = 8
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Plot (0,-6) and (8,0) and draw a line thru them to get:
F(x) = 8x-x^2 only if x is equal to 8 or less than 8
OR
f(x) = x^2+3 only if x > 8
We can only pick one of the two paths. The function f(x) can't be both at the same time. In the case of computing f(8) we have the input x = 8. It won't fit the bottom piece as x > 8 is false when x = 8. The inequality 8 > 8 is false
So instead we pick the top piece
x = 8 ----> so "x is less than or equal to 8" is true
f(x) = 8x - x^2
f(8) = 8*8 - 8^2
f(8) = 64 - 64
f(8) = 0
The final answer is 0
Answer:
![\large\boxed{f(x)=x^2+16x+60}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bf%28x%29%3Dx%5E2%2B16x%2B60%7D)
Step-by-step explanation:
The factored form of a quadratic function:
![f(x)=ax^2+bx+c=a(x-x_1)(x-x_2)](https://tex.z-dn.net/?f=f%28x%29%3Dax%5E2%2Bbx%2Bc%3Da%28x-x_1%29%28x-x_2%29)
x₁, x₂ - the zeros
We have x₁ = -10 and x₂ = -6.
Substitute:
![f(x)=(x-(-10))(x-(-6))=(x+10)(x+6)](https://tex.z-dn.net/?f=f%28x%29%3D%28x-%28-10%29%29%28x-%28-6%29%29%3D%28x%2B10%29%28x%2B6%29)
Use FOIL: <em>(a + b)(c + d) = ac + ad + bc + bd</em>
![f(x)=(x)(x)+(x)(6)+(10)(x)+(10)(6)\\\\f(x)=x^2+6x+10x+60\\\\f(x)=x^2+16x+60](https://tex.z-dn.net/?f=f%28x%29%3D%28x%29%28x%29%2B%28x%29%286%29%2B%2810%29%28x%29%2B%2810%29%286%29%5C%5C%5C%5Cf%28x%29%3Dx%5E2%2B6x%2B10x%2B60%5C%5C%5C%5Cf%28x%29%3Dx%5E2%2B16x%2B60)
Thus, how much the change affects the surface area depends on the relative initial measurements of r and h.