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Ierofanga [76]
3 years ago
15

Pls help me!! I just need help on both of the following questions, a-d on each

Mathematics
1 answer:
Ymorist [56]3 years ago
7 0
I'll do a and e on the first one to show you how to do it

Then See if you can do the rest

a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative

So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18

e. -20 ÷ 5

same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4

You do b, c, d, and f on the first question. Tell me what you get and we'll go from there

</span>Now for the second question <span>

</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)

</span>a. 4(-2 \frac{1}{3}) + 7 \frac{1}{6}
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator

</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>

but when you times a negative by a negative you get a positive


Now you try b and c; let me know what you get, and we'll go from there!

</span>

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Answer:

0.164 = 16.4% probability that at least one color will be missing from the 10 selected balls.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Determine the probability that at least one color will be missing from the 10 selected balls.

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Each time, there are 55 + 25 = 80 non-red balls, out of 100. So, in each of the 10 trials, 80% = 0.8 probability of not picking a red ball. The probability that no red ball is picked is given by:

(0.8)^10 = 0.1074

White missing:

55 + 20 = 75 non-white balls, out of 100, in each trial. The probability that no white ball is picked is given by:

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Total:

0.1074 + 0.0563 + 0.0003 = 0.164

0.164 = 16.4% probability that at least one color will be missing from the 10 selected balls.

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