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mamaluj [8]
3 years ago
6

I don’t know what to do after this

Mathematics
1 answer:
Bumek [7]3 years ago
8 0

THE answer is 7 1/6 Please go to cymath and you’ll see how to work it out


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Find the standard deviation of the data, 12, 19, 9.
jek_recluse [69]

Answer:

4.19

Step-by-step explanation:

Find the mean:

\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}

Find the standard deviation:

\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19

4 0
2 years ago
F(x)=2x+3 find x=9 explain how you got the answer please help me I need the answer today
hram777 [196]
You would fill in 9 for x so your equation would be 2(9)+3 and you would then get 21. Therefore the answer is f(x)=21
6 0
3 years ago
If a+b=2 find the value of a3+b3+6ab
mars1129 [50]

Answer:

Step-by-step explanation:

Factor the sum of cubes

a³ + b³ = (a+b)(a² - ab +b²)

= 2a² - 2ab + 2b²

a³ + b³ + 6ab = 2a² + 4ab + 2b²

= 2(a² + 2ab +b²)

= 2(a+b)²

= 8

7 0
3 years ago
Ace does various odd jobs over the summer on one of his jobs he was paid $81 for a job he completed in nine hours. if he average
Vikentia [17]
He is making $9 an hour bc 81/9=9
9x26=$234
9x35=$315
after working 26 full hours he will have made a total of $234
total earnings:$315

I hope that is what you were looking for!
8 0
3 years ago
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation of 1.4. The distributio
posledela

Answer:

Approximate probability that \overline{X} is less than 2 = 0.1515

Step-by-step explanation:

Given -

Mean (\nu ) = 2.2

Standard deviation (\sigma  ) = 1.4

Sample size ( n ) = 52

Let  \overline{X} be the mean of accidents per week at the intersection during one year (52 weeks) .

probability that \overline{X} is less than 2 =

P(\overline{X}< 2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}< \frac{2 - 2.2 }{\frac{1.4}{\sqrt{52}}})   Putting (Z =\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}})

                 = P(Z< - 1.03)    ( Using Z table )

                 = 0.1515

7 0
3 years ago
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