Answer:
A
Step-by-step explanation:
common ratio of 0.5.
hmu for more
43 is a 2-digit odd number but it isn't composite. It's a prime number.
Hope this helps. :)
You should draw a picture to visualize the problem easier.
The circumference of inner circle = 44 ft
That means the radius of the inner circle:
2*pi*r = 44
r = 44/(2pi) = 22/pi
Using the picture you hopefully drew, we see that the radius of the outer circle:
22/pi + 2
To figure out the circumference of the outer circle:
2pi*(22/pi + 2) = 44 + 4pi
So how much bigger is the the circumference of the outer circle than the inner circle?
44 + 4pi - 44 = 4pi
It is 4pi bigger or 4 * (3.14) = 12.56 feet
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:
4(2e - 3)(3e + 1)
Step-by-step explanation:
Given
24e² - 28e - 12 ← factor out 4 from each term
= 4(6e² - 7e - 3) ← factor the quadratic
Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.
product = 6 × - 3 = - 18 and sum = - 7
The factors are - 9 and + 2
Use these factors to split the e- term
6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )
= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term
= (2e - 3)(3e + 1)
Then
24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form
