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Maurinko [17]
4 years ago
9

What do elements in the first two columns of the periodic table have in common?

Chemistry
1 answer:
ololo11 [35]4 years ago
3 0

All of them are very reactive.

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What kind of data would you need to collect to carry out this experiment?
JulijaS [17]
You need to specify the experiment to get an answer.  However, most experiments require qualitative data (descriptive, non-numerical data) and quantitative data (measured, numerical data).
4 0
4 years ago
What mass of hydrogen is produced from 5.71 mol of aluminum?
nasty-shy [4]

Answer:

3.03 g

Explanation:

The first thing to do here is figure out the chemical formula for aluminium hydroxide.

Aluminium is located in group

13

of the periodic table, and forms

3

+

cations,

Al

3

+

. The hydroxide anion,

OH

−

, carries a

1

−

charge, which means that a formula unit of aluminium hydroxide will look like this

[

Al

3

+

]

+

3

[

OH

−

]

→

Al

(

OH

)

3

Now, you can figure out the mass of hydrogen present in

1

mole of aluminium hydroxide by first determining how many moles if hydrogen you get in

1

mole of aluminium hydroxide.

Since

1

mole of aluminium hydroxide contains

3

moles of hydroxide anions, which in turn contain

1

mole of hydrogen each, you can say that you will have

1 mole Al

(

OH

)

3

→

3

a

moles OH

−

→

3

a

moles H

The problem tells you that the molar mass of hydrogen is equal to

1.01 g mol

−

1

. This means that

1

mole of hydrogen has a mass of

1.01 g

.

You can thus say that one mole of aluminium hydroxide contains

3

moles H

⋅

1.01 g

1

mole H

=

a

a

3.03 g H

a

a

∣

∣

I'll leave the answer rounded to three sig figs. Btw my sister calculated this oof

5 0
3 years ago
How many moles are in 3.4×10^23 molecules of H2SO4
Kazeer [188]
1 mole ----------- 6.02x10²³ molecules
? moles ---------- 3.4x10²³ molecules

(3.4x10²³) x 1 / 6.02x10²³ =

3.4x10²³ / 6.02x10²³ => 0.564 moles of H2SO4
6 0
3 years ago
011 10.0 points
Sphinxa [80]

Answer:

-58.3^{\circ}C

Explanation:

The frequency and the wavelength of a wave are related by the equation

v=f\lambda

where

v is the speed

f is the frequency

\lambda is the wavelength

For the sound wave in this problem, we have

f = 634 Hz (frequency)

\lambda=0.47 m (wavelength)

Therefore, the speed of the wave is

v=(634)(0.47)=298 m/s

The speed of sound in air depends on the temperature according to the equation

v=333+0.6 T

where T is the temperature.

In this problem, we know the speed, so we can calculate the temperature:

T=\frac{v-333}{0.6}=\frac{298-333}{0.6}=-58.3^{\circ}C

7 0
3 years ago
N2+3H2 forms 2NH3
Nookie1986 [14]

ok ther only one solution n2 is ÷ 2h×2 is ok but the problem is that the standard form of the square is not yet

4 0
2 years ago
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