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3 years ago

F(x) = (2/5)^x g(x) = (2/5)^x– 3

2 answers:

6 0

Letter C
The - 3 at the end of the function means the function is shifted down 3 units. This also shifts the asymptote down 3 units.

vagabundo [1.1K]3 years ago

3 0

Answer:

it is definitely c

Step-by-step explanation:

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As shown:

Angle C = Angle f = 127

The length of fe = the length of CA = 2 units

Angle E = Angle A = 40

So, triangle ABC = triangle EDF by ASA

The answer is option 2

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1 year ago

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Step-by-step explanation:

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2 years ago

\int\limits^0_∞ cos{x} \, dx

JulijaS [17]

Answer:

$\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty)$

General Formulas and Concepts:

Pre-Calculus

Unit Circle
Trig Graphs

Calculus

Limits
Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$
Integrals
Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$
Trig Integration
Improper Integrals

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^0_\infty {cos(x)} \, dx$

Step 2: Integrate

[Improper Integral] Rewrite: $\displaystyle \lim_{a \to \infty} \int\limits^0_a {cos(x)} \, dx$
[Integral] Trig Integration: $\displaystyle \lim_{a \to \infty} sin(x) \bigg| \limits^0_a$
[Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle \lim_{a \to \infty} sin(0) - sin(a)$
Evaluate trig: $\displaystyle \lim_{a \to \infty} -sin(a)$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle -sin(\infty)$

Since we are dealing with infinity of functions, we can do a numerous amount of things:

Since -sin(x) is a shift from the parent graph sin(x), we can say that -sin(∞) = sin(∞) since sin(x) is an oscillating graph. The values of -sin(x) already have values in sin(x).
Since sin(x) is an oscillating graph, we can also say that the integral actually equates to undefined, since it will never reach 1 certain value.

∴ $\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty) \ or \ \text{unde}\text{fined}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Improper Integrals

Book: College Calculus 10e

7 0

2 years ago