If f(x, y)=xy−x^2, what is the value of f(f(−2, 3), −4)? Explain your reasoning.

1 answer:

hjlf3 years ago

3 0

$\bf f(x,y)=xy-x^2 \\\\[-0.35em] ~\dotfill\\\\ f(\stackrel{x}{-2},\stackrel{y}{3})=(-2)(3)-(-2)^2\implies f(-2,3)=-6-(4)\implies f(-2,3)=-10 \\\\[-0.35em] ~\dotfill\\\\ f(~~\underline{f(-2,3)},~~-4)\implies f(\stackrel{x}{\underline{-10}},\stackrel{y}{-4})=(-10)(-4)-(-10)^2 \\\\\\ f(-10,-4)=40-(100)\implies f(-10,-4)=-60$

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A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so $\mu = 145, \sigma = 25$ .