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rosijanka [135]
3 years ago
7

In which quadrant is the point ( - 3 , -5) ?

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

3

Step-by-step explanation:

Since both coordinates are negative, the coordinate is in quadrant 3.

pogonyaev3 years ago
3 0
Quadrant 3 Because they are both negative numbers and that is what quadrant 3 handles so. Hope this helps!
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Write the complex number in the form a + bi. 6(cos 330° + i sin 330°) -3square root of three - 3i -3square root of three + 3i 3s
torisob [31]

Answer:

The complex number in rectangular form is z = 3\sqrt{3}-i\,3.

Step-by-step explanation:

Let be a complex number in polar form, that is: z = r\cdot (\cos \theta + i\,\sin \theta). The equivalent expression in rectangular form is defined by z = a+i\,b, where:

a = r\cdot \cos \theta (1)

b = r\cdot \sin \theta (2)

Where:

r - Magnitude.

\theta - Direction, measured in sexagesimal degrees.

If we know that r = 6 and \theta = 330^{\circ}, then complex number in rectangular form is:

a = 6\cdot \cos 330^{\circ}

a = 3\sqrt{3}

b = 6\cdot \sin 330^{\circ}

b = -3

The complex number in rectangular form is z = 3\sqrt{3}-i\,3.

3 0
3 years ago
I need help PLSSSSS. ASAP​
Gala2k [10]
119.25 is the right answer for this question
6 0
3 years ago
Write an equation in slope-intercept form for each graph shown
Sonbull [250]

Answer:

Pic 1: y=(-3/5)x+4

Pic 2: y=(1/4)x-4

Step-by-step explanation:

4 0
3 years ago
How many zero pairs must be added to the function
konstantin123 [22]
TO write the function into vertex form, we need to add one zero and the solution is shown below:
f(x)= x² -6x +1
Add one zero in the form of -9 and 9, such as:
f(x) = x² -6x +1 -9 +9
f(x) = (x² -6x +9) +(1-9)
f(x) = (x-3)² + (-8)
f(x) = (x-3)² - 8
This is the vertex form of the given function and only one zero is being added.
3 0
3 years ago
Read 2 more answers
What is the area of a sector with radius 6" and measure of arc equal to 120°?
fenix001 [56]
The area of a sector = 0.5 * radius^2 * central angle measure (in radians)

So that:

Area_{sector}=  \frac{1}{2} * 6^2* \frac{120}{180}*\pi=12\pi=37.69911
\\
Area_{sector}=37.7 sq in

7 0
3 years ago
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