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2 years ago

In which quadrant is the point ( - 3 , -5) ?

Mathematics

2 answers:

Dmitry_Shevchenko [17]2 years ago

7 0

Answer:

Step-by-step explanation:

Since both coordinates are negative, the coordinate is in quadrant 3.

pogonyaev2 years ago

3 0

Quadrant 3 Because they are both negative numbers and that is what quadrant 3 handles so. Hope this helps!

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4(2x+7) +3 (2x+7) but (2x+7) is equal to 2

vodomira [7]

Use the distributive property to get 8x+28+6x+21 then combine 8x and 6x and also combine 28 and 21 to get 14x+49, do u need to go further or?

6 0

3 years ago

consider the following scenario: Assume daily protein intake values in a population of athletes are known to have a standard dev

Kipish [7]

Answer:

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{58.6}{\sqrt{267}} = 7.03$

The lower end of the interval is the sample mean subtracted by M. So it is 77 - 7.03 = 69.97g.

The upper end of the interval is the sample mean added to M. So it is 77 + 7.03 = 84.03g.

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

5 0

3 years ago

2. The cost of having a window fixed is $100 plus $20 per hour of labor. Using h for the number of hours of labor, write an expr

ahrayia [7]

Answer:

the third one

Step-by-step explanation:

I hope this helps with your question :)

5 0

2 years ago

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.

Naya [18.7K]

It's a geometric sequence.

$4,-12,36,... \\ \\
a_1=4 \\
r=\frac{a_2}{a_1}=\frac{-12}{4}=-3 \\ \\
a_n=a_1 \times r^{n-1} \\
a_n=4 \times (-3)^{n-1} \\
a_n=4 \times (-3)^{-1} \times (-3)^n \\
a_n=4 \times (-\frac{1}{3}) \times (-3)^n \\
a_n=-\frac{4}{3}(-3)^n$

It's the sum for term 4 through term 15.

$\boxed{ \sum\limits_{n=4}^{15} (\frac{4}{3}(-3)^n)}$

8 0

2 years ago

if α and β are the zeroes of the polynomial 3x^2 - 8x − 3 then find the value of i) α^2 + β^2 ii) α^-1 + β^-1

BlackZzzverrR [31]

Step-by-step explanation:

the answer is in the above image

5 0

2 years ago