Answer: OPTION B.
Step-by-step explanation:
The missing figure is attached.
For this exercise you need to use the Pythagorean Theorem. This is:
![a^2=b^2+c^2](https://tex.z-dn.net/?f=a%5E2%3Db%5E2%2Bc%5E2)
Where "a" is the hypotenuse and "b" and "c" are the legs of the triangle.
In this case you can identify in the figure the triangle PRS, so the diagonal PR is the hypotenuse of the triangle PRS.
Then you can say that:
![a=PR\\b=PS=17\\c=RS=33](https://tex.z-dn.net/?f=a%3DPR%5C%5Cb%3DPS%3D17%5C%5Cc%3DRS%3D33)
Therefore, knowing these values, you can substitute them into
:
![PR^2=17^2+33^2](https://tex.z-dn.net/?f=PR%5E2%3D17%5E2%2B33%5E2)
Finally you must solve for PR in order to find its value. This is:
![PR=\sqrt{17^2+33^2}\\\\PR=37.12](https://tex.z-dn.net/?f=PR%3D%5Csqrt%7B17%5E2%2B33%5E2%7D%5C%5C%5C%5CPR%3D37.12)
Answer: See explanation
Step-by-step explanation:
You didn't give any figures but let me try and help out.
The area of a circle is given as:
= πr²
Let's say we have radius as 8m, the are will be:
= πr²
= 3.14 × 8²
= 3.14 × 64
= 200.96m²
The answer to your problem should be 5 wholes and 5/6 since the denominators are the same just add 6 more pieces to 4/6 to get an improper fraction then subtract to get the answer. Hope this helps and have a fabulous day!
Answer:
5/7
Step-by-step explanation: