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4 years ago

What is the resulting ordered pair if the value of the independent variable is 5?

Mathematics

1 answer:

eduard4 years ago

6 0

Ｆ（５）　＝　－２　＊　５　＋　１　＝　－９
ｔｈｅ　ｐａｉｒ　ｉｓ　（５，　－９）

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Set up and solve an equation for the value of x. Use the value of x and a relevant angle relationship in the diagram

Fudgin [204]

Answer:

x and EAF are 27 degrees

Step-by-step explanation:

Since GAF is a right angle as indicated by the little square, GAC and CAF must add up to 90 degrees. Therefore, x is 90-63=27 degrees. The situation is the same for angle EAF. Hope this helps!

7 0

3 years ago

I HAVE LIKE 2 MORE QUESTIONS, HELP ME PLZ!

Ne4ueva [31]

Given:

Base length of triangle = 10 units

Height of triangle = $\sqrt{44}$ units

Length of hypotenuse of triangle = 12 units

To find:

Exact value of Cos A

Steps:

The cosine of any angle is equal to the length of the adjacent side by the length of the hypotenuse side.

So,

Cos A = $\frac{adjacent}{hypotenuse}$

Cos A = $\frac{10}{12}$

Cos A = 0.833

Therefore, the exact value of cos A is 0.833.

Happy to help :)

If u need any help, feel free to ask

5 0

3 years ago

What is the midpoint between (3, -1) and (7,-5)

Alex Ar [27]

Answer:

(5, -3)

Step-by-step explanation:

given two points (x₁, y₁) and (x₂, y₂), the midpoint is $(\frac{x_1+x_2}{2} ,\frac{y_1 + y_2}{2})$

$(\frac{3+7}{2} ,\frac{-1 + -5}{2})$ = $(\frac{10}{2} ,\frac{-6}{2}) = (5, -3)$

6 0

3 years ago

The mean cost of a five pound bag of shrimp is 40 dollars with a standard deviation of 7 dollars. If a sample of 51 bags of shri

eimsori [14]

Answer:

$P(|\bar{x}-40| > 0.6)=0.5404$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 40 dollars

Standard Deviation, σ = 7 dollars

Sample size,n = 51

We are given that the distribution of cost of shrimp is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{7}{\sqrt{51}} = 0.9801$

P(sample mean would differ by true mean by more than 0.6)

$P(|\bar{x}-40| > 0.6)\\\Rightarrow = 1-P(39.4$

$P(39.4 \leq x \leq 40.6) \\\\= P(\displaystyle\frac{39.4 - 40}{0.9801} \leq z \leq \displaystyle\frac{40.6-40}{0.9801})\\\\ = P(-0.6121 \leq z \leq 0.6121)\\= P(z \leq 0.6121) - P(z < -0.6121)\\= 0.7298 - 0.2702 =0.4596$

$P(|\bar{x}|-40 > 0.6)\\= 1-0.4596=0.5404$

0.5404 is the required probability.

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3 years ago

(4x)° (5x+18)° 81° solve for x

tamaranim1 [39]

Answer: If you see my picture and you will see my answer

Step-by-step explanation: Hope this help

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3 years ago